10 cls
11 c = 0
20 for n =1 to 10
30 input"enter no.";a
40 c=c+a
50 next n
60 print c
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;
Cls input "enter two no.s ",a,b sum=a+b print "sum = ";sum end
5
int sum (int min, int max) {return (max-min+1)*(max+min)/2;}
It depends on the series.
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
You use the relevant formula.
The nos. Are 8 and -8 Sum of the nos. 8+(-8)=0 Product of the nos. 8 × (-8) = -64
148
Each one of them can be expressed as a sum of two primes.
-- Think of a name for the sum, like 'S'.-- Tell qbasic what 'S' is the sum of.S = 41 + 61 + 2 + 84 + 136-- If you want to see it on the screen, thenPRINT Sand the sum pops up. It looks like this on the screen:324
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
11x11
777/3 = 259. So the numbers are 258, 259 and 260.
2 and 3.