image is shared
The Josephus problem is a problem to locate the place for the last survivour. It shows the power of the circular linked list over the singly linked lists.
What is your question about it?It is quite possible, for example if it is a circular list, having a 'sentinel' node.typedef struct ListE {struct ListE *next;...} ListE;ListE listhdr;listhdr.next = &listhdr; /* empty list */
write pseudocode for link list
Oh, dude, a linear linked list is like a straight line where each element points to the next one, while a circular linked list is like a loop-de-loop rollercoaster where the last element points back to the first one. So, in a linear list, you reach the end and it's like hitting a wall, but in a circular list, you just keep on looping around for eternity. It's like the difference between a dead-end street and a roundabout.
The default constructor of a stack is empty because the default value of any container, including a linked list, is an empty container which requires no arguments (all members default to zero).
A linked list is circular if the tail of the list points to the head. The easiest way to check this is to check whether the pointer of the tail is a null pointer. If it is, then the list is not circular.
LINEAR STRAIGHT CIRCULAR CURVED
A doubly linked list is a linked list in which each node knows where both of its neighbors are.A circular linked list is a linked list in which the "tail" of the list is linked to the "root". (Note that both the tail and root of the list are undefined/arbitrary in a circular linked list)Doubly linked lists are actually not necessarily related to circular linked list (aside from both being based on a linked list structure). In fact, you can have a circular doubly linked list, where each node knows where both of its neighbors are andwhere the list wraps around to connect to itself.
The Josephus problem is a problem to locate the place for the last survivour. It shows the power of the circular linked list over the singly linked lists.
if the last node contains the address of head node instead of null then it is a circular linked llist...
What is your question about it?It is quite possible, for example if it is a circular list, having a 'sentinel' node.typedef struct ListE {struct ListE *next;...} ListE;ListE listhdr;listhdr.next = &listhdr; /* empty list */
You'll need to use a doubly-linked circular list, since otherwise when you pop off the tail element you'll need to whizz all the way round the list to find its predecessor. See the links section for an implementation of a doubly-linked circular list.
write pseudocode for link list
In a circular linked list every node is connected to another node. In a non-circular linked list. There are definitely starting and ending nodes are lacking an incoming and outgoing link, respectively.
circular linked list is type of linked list used in data structure where address of 1st node is stored in the link part of last node data1link1 ................... datanlinkn address1 here linkn=adress1 (node1) (noden) pratima patwa
Oh, dude, a linear linked list is like a straight line where each element points to the next one, while a circular linked list is like a loop-de-loop rollercoaster where the last element points back to the first one. So, in a linear list, you reach the end and it's like hitting a wall, but in a circular list, you just keep on looping around for eternity. It's like the difference between a dead-end street and a roundabout.
The default constructor of a stack is empty because the default value of any container, including a linked list, is an empty container which requires no arguments (all members default to zero).