The combined resistance is 7.6049 ohms.
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
If the two resistors are in series, then the larger one is 2 ohms.(The smaller one is 1 ohm. Their combined series total is 3 ohms. 9/3 = 3 amps.)If the two resistors are in parallel, then the larger one is 9 ohms.(The smaller one is 4.5 ohms. The combined parallel total is 3 ohms. 9/3 = 3 amps.)
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
(R1 x R2) / (R1 + R2) for 2 load parallel circuits, soo... 133.3 repeating Ohms.
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.
The equivalent resistance of four resistors in parallel, the resistors being 2, 4, 6, and 8 ohms, is 0.96 ohms. RP = 1 / summationI=1toN (1/RI)
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
You can achieve an effective resistance of 3 ohms by connecting the resistors in series. Connect two resistors in series to get a combination of 4 ohms. Then, connect this combination in parallel with the third resistor to achieve an overall resistance of 3 ohms.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
If the two resistors are in series, then the larger one is 2 ohms.(The smaller one is 1 ohm. Their combined series total is 3 ohms. 9/3 = 3 amps.)If the two resistors are in parallel, then the larger one is 9 ohms.(The smaller one is 4.5 ohms. The combined parallel total is 3 ohms. 9/3 = 3 amps.)
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
You can achieve a 30 ohm equivalent resistance by connecting the resistors in a combination of series and parallel. Connect two resistors in series to get 40 ohms, then connect the third resistor in parallel with this combination to achieve a total resistance of 30 ohms.
The equivalent resistance of resistors connected in series is simply the sum of their individual resistances. Therefore, the equivalent resistance of three 8.0-W resistors connected in series is 24.0 W.
(R1 x R2) / (R1 + R2) for 2 load parallel circuits, soo... 133.3 repeating Ohms.