You already said the answer that b is less than c
The answer is A 90.03
Well, isn't that just a happy little math problem! If A is less than B and B plus C equals 10, then it must be true that A plus C is less than 10. Just remember, in the world of numbers, everything adds up beautifully in the end.
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
(Uses Square Root Function) PRINT "Ax^2 + Bx + C = 0" INPUT "A = ", A INPUT "B = ", B INPUT "C = ", C D = B * B - 4 * A * C IF D > 0 THEN DS = SQR(D) PRINT "REAL ROOTS:", (-B - D) / (2 * A), (-B + D) / (2 * A) ELSE IF D = 0 THEN PRINT "DUPLICATE ROOT:", (-B) / (2 * A) ELSE DS = SQR(-D) PRINT "COMPLEX CONJUGATE ROOTS:", (-B / (2 * A)); "+/-"; DS / (2 * A); "i" END IF END IF
#include<stdio.h> #include<conio.h> void main() { int a,b,c; clrscr(); printf("Enter any three numbers"); scanf("%d%d%d",&a,&b,&c); if(a>b&&a>c) printf("A is greatest"); else if(b>a&&a>c) printf("B is greatest"); else if(c>a&&c>b) printf("C is greatest"); if(a<b&&a<c) printf("A is smallest"); else if(b<a&&b<c) printf("B is smallest"); else if(c<a&&c<b) printf("C is smallest"); getch(); }
a < b < c So, neither a nor b is greater than c.
NO it is not because if a<b<c it could also be said without the b as a<c.
Correct.
Absolutely not
False. A is greater than C. ******************** I'm not in calculus but if A isn't less than B, then that means its either greater than or equal to it. and if B isn't less than C then its greater or equal to. so that means that A is either greater than or equal to C. so that means that A than C.
A is greater than B (A>B). C is less than D (C<D). But what about "less than or equal"?
4
a is 6 less than d.
It is not possible to answer the question without any information on what a, b and c are.
I believe that's usually treated as an axiom, meaning you don't prove it.
A plus b plus c equals d. A is the largest answer b is the smallest answer and d is less than 6?''
B. 6.0 is less than 6.001.