9, the elements are: arr[0], arr[1], ... arr[9]
To calculate the size of array the type of array should be given. Ex: if it is of integer type that means int arr[100] and integer is of 4 bytes, then the size of array will be 400 bytes.
#include <stdio.h> #include <stdlib.h> #define size 50 void swap(int *x,int *y) { int temp; temp = *x; *x = *y; *y = temp; } int partition(int i,int j ) { return((i+j) /2); } void quicksort(int list[],int m,int n) { int key,i,j,k; if( m < n) { k = partition(m,n); swap(&list[m],&list[k]); key = list[m]; i = m+1; j = n; while(i <= j) { while((i <= n) && (list[i] <= key)) i++; while((j >= m) && (list[j] > key)) j--; if( i < j) swap(&list[i],&list[j]); } // swap two elements swap(&list[m],&list[j]); // recursively sort the lesser list quicksort(list,m,j-1); quicksort(list,j+1,n); } } void printlist(int list[],int n) { int i; for(i=0;i<n;i++) printf("%d\t",list[i]); } void main() { int n,i; int list[size]; printf("How many numbers do you want to enter"); scanf("%d",&n); printf("Enter the numbers you want to sort"); for(i=0;i<n;i++) { scanf("%d",&list[i]); } printf("The list before sorting is:\n"); printlist(list,n); // sort the list using quicksort quicksort(list,0,n-1); // print the result printf("The list after sorting using quicksort algorithm:\n"); printlist(list,n); }
int linearSearch(int a[], int first, int last, int key) { // function: // Searches a[first]..a[last] for key. // returns: index of the matching element if it finds key, // otherwise -1. // parameters: // a in array of (possibly unsorted) values. // first, last in lower and upper subscript bounds // key in value to search for. // returns: // index of key, or -1 if key is not in the array. for (int i=first; i<=last; i++) { if (key == a[i]) { return i; } } return -1; // failed to find key }
// declare a function int* function(int, int); or int* (function)(int, int); // declare a pointer to a function int* (*pointer_to_function)(int, int);
printf ("sizeof (int) = %d\n", (int)sizeof (int));
Lower bound is 17.6 and upper bound is 17.8
A function whose upper bound would have attained its upper limit at a bound. For example, f(x) = x - a whose domain is a < x < b The upper bound is upper bound is b - a but, because x < b, the bound is never actually attained.
The answer is B.
An upper bound estimate is a estimate that is greater than the actual solution.
Let (B, ≤) be a partially ordered set and let C ⊂ B. An upper bound for C is an element b Є Bsuch that c ≤ b for each c Є C. If m is an upper bound for C, and if m ≤ b for each upper bound b of C, then m is a least upper bound of C. C can only have one least upper bound, and it may not have any at all (depending on B). The least upper bound of a set C is often written as lub C.See related links for more information.
The upper bound of a number is the smallest value that is greater than or equal to that number. For 21.4, the upper bound can be considered as 21.5, since it is the next decimal value that exceeds 21.4. However, in a more general context, any number greater than 21.4 can also serve as an upper bound.
Big O gives an upper bound whereas big theta gives both an upper bound and a lower bound.
The upper bound is the size minus 1 since VB starts with zero not one.
4.46 is a fixed number: it has no upper nor lower bound. To 2 dp it is 4.46
The upper bound of a number is the smallest whole number that is greater than or equal to the given number. In this case, the upper bound of 6800 is 6800 itself. The lower bound of a number is the largest whole number that is less than or equal to the given number. Therefore, the lower bound of 6800 is also 6800.
The lower bound is 0.5 less and the upper bound is 0.5 more.
To calculate the size of array the type of array should be given. Ex: if it is of integer type that means int arr[100] and integer is of 4 bytes, then the size of array will be 400 bytes.