The upper bound is the size minus 1 since VB starts with zero not one.
101
101
To calculate the size of array the type of array should be given. Ex: if it is of integer type that means int arr[100] and integer is of 4 bytes, then the size of array will be 400 bytes.
it's late bound
The asymptotic upper bound for the time complexity of the algorithm is the maximum amount of time it will take to run, as the input size approaches infinity.
An array is simply a contiguous block of memory that is divided into one or more elements of equal size. The array name is itself a reference to the start address of the array, which has the same address as the first element in the array (the element with index 0). The index is essentially an offset from the start of the array, multiplied by the size of an element. However, there is no built-in mechanism in C to prevent you from accessing elements beyond the upper bound of the array at runtime -- essentially overflowing the array. Since C++ inherits from C, the same problem exists in C++. For instance, in a 10 element array, the upper bound is 9. If you attempt to write to element 10, you are overflowing the array, the buffer, because that memory does not belong to the array. You then introduce undefined behaviour. At best, nothing bad will happen. At worst, people could die. Once you introduce undefined behaviour there's simply no telling what could happen -- it's a time-bomb waiting to go off. The only way to avoid such problems is to ensure all your array offsets remain within the bounds of the array. That is, the onus is upon the C++ programmer -- just as it still is with the C programmer.
#include "stdio.h" #define SIZE 100; void main() { int array[SIZE], i, size; printf("\nEnter the Size off Array :- "); scanf("%d", &size); printf("\nEnter the Elements of Array :- ")' for(i = 0; i < size; i++) scanf("%d", &array[i]; printf("\nThe Elements of entered Array :- "); for(i = 0; i < size; i++) printf("%7d", array[i]); }
To get the size of an array in C, you can use the sizeof() operator. This operator returns the number of bytes occupied by the array, so to get the number of elements in the array, you can divide the total size by the size of one element.
! variable to declase the size of an array in True Basic ! set up a dummy value for array - any initial value > 0 is fine. DIM array$(999) ! ask the user for the length of the array INPUT PROMPT "Enter array size " :size ! resize the array with user defined length MAT REDIM array$(size) ! program end END
void bubblesort (int* array, int size) { if (!array size<2) return; int last_swap = size; while (last_swap>0) { int n=last_swap; for (int i=1; i<last_swap; ++i) { if (array[i]<array[i-1]) { array[i]^=array[i-1]^=array[i]^=array[i-1]; n=i; } last_swap = n; } }
Some immediate disadvantages:You'll have dead space in the array (entries which aren't currently used for items) taking up memoryYou'll have to keep track of the free entries - after a few insertions and deletions, these free entries could be anywhere.Using an array will impose an upper limit on the size of the linked list.
The maximum number of entries that can be placed in a chained hash table is determined by the size of the underlying array used for storage. Each bucket in the array can hold multiple entries due to chaining, so the total number of entries that can be stored is dependent on the size of the array and the hashing function used.