cin is an object........ An Example is // By Codex
#include <iostream> using namespace std; int main(){ int age;
cout << "How Old Are You?\n";
cin >> age;
cout << "You are << age << years old\n";
system("pause")
return 0;
}
scanf is a function (available in C and C++)cin is an istream object (C++ only)Advice: when in doubt, use fgets+sscanf
cin is the object of istream class i.e, input class.
input is the << operator and output is the >> operator
You are completely wrong here.Another answer:There is nothing to say you cannot use cin or coutoutside the main() function (for example, you can use them in a function called from main()). However, using them before main() has been called (e.g. in the constructor of a static object) can have disastrous consequences: cin and cout are themselves static objects, and static initialisation order is undefined. Thus you could be calling them before they have been properly constructed.
void foo (char& c) { cin >> c; } int main() { char ch[10] {}; for (size_t c=0; c!=10; ++c) foo (c[0]); }
scanf is a function (available in C and C++)cin is an istream object (C++ only)Advice: when in doubt, use fgets+sscanf
cin is the object of istream class i.e, input class.
input is the << operator and output is the >> operator
No. In C++ with <iostream>, cin is a prefedined class that represents stdin, so it is an input identifier.
The operator required to call c function using object name is function object. Other operator names that deal with objects are structure dereference, structure reference, and indirection
You are completely wrong here.Another answer:There is nothing to say you cannot use cin or coutoutside the main() function (for example, you can use them in a function called from main()). However, using them before main() has been called (e.g. in the constructor of a static object) can have disastrous consequences: cin and cout are themselves static objects, and static initialisation order is undefined. Thus you could be calling them before they have been properly constructed.
void foo (char& c) { cin >> c; } int main() { char ch[10] {}; for (size_t c=0; c!=10; ++c) foo (c[0]); }
cin and cout are synonymous with stdin and stdout, implementing console input and output respectively.
method
No, because there are no objects in C.
In C++ (C Plus Plus), when you call by reference, you are directly accessing the data of the referenced object. When you pass an object to a function by reference, any and all alterations to the object made within the function carry through to the actual object.
In C++ (C Plus Plus), when you call by reference, you are directly accessing the data of the referenced object. When you pass an object to a function by reference, any and all alterations to the object made within the function carry through to the actual object.