Programm to calculate and display no of each differebt character present in a string suppose String is Mumbai output should be M2u1b1a1i1?

Answer 1

In Java

// the string we want to process

final String str = "Mumbai";

// convenience conversion to characters

final char[] str_chars = str.toCharArray();

// letters used to keep track of which characters we've counted

final Set letters = new HashSet();

// iterate through each character in str

for (int i = 0; i < str_chars.length; ++i) {

// store lower case version of ch so we only need to convert once

final char ch_l = Character.toLowerCase(str_chars[i]);

// only process this letter if we haven't done so yet

if (!letters.contains(ch_l)) {

// store letter

letters.add(ch_l);

// count number of times this letter is in str

int count = 1;

for (int j = i + 1; j < str_chars.length; ++j) {

if (ch_l == Character.toLowerCase(str_chars[j])) {

++count;

}

}

// output

System.out.format("%c%d", str_chars[i], count);

}

}