It can't, unless there's some other coil, such as a bunch of wire between the two, or you're measurement equipment is off. Two inductors in series will have the same inductance as the two summed together.
Inductors in series add up, so 15 mH
When inductors are connected in parallel, the total inductance (L_total) can be calculated using the formula: (\frac{1}{L_{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3}). For the given inductors, this becomes: (\frac{1}{L_{total}} = \frac{1}{0.06} + \frac{1}{0.05} + \frac{1}{0.1}). Calculating this yields (L_{total} \approx 0.017 H) or 17 mH.
To find the total inductance ( L_t ) of two inductors in parallel, you can use the formula: [ \frac{1}{L_t} = \frac{1}{L_1} + \frac{1}{L_2} ] For two identical inductors of 22 mH, this simplifies to: [ \frac{1}{L_t} = \frac{1}{22 , \text{mH}} + \frac{1}{22 , \text{mH}} = \frac{2}{22 , \text{mH}} = \frac{1}{11 , \text{mH}} ] Thus, the total inductance ( L_t ) is 11 mH.
Inductors can be used for a great many purposes. Terms, such as 'choke', 'reactor', etc., describe applications of inductors.
actually, inductance is directly proptional to the frequency according to the formula , so if frequency is more, then inductance is also more and vice versa
Inductance in series is the sum of the individual inductances.
Inductors are connected in series in order to increase the inductance in the circuit.
Inductance in parallel is the reciprocal of the sum of the reciprocals of the individual inductance's. LPARALLEL = 1 / SummationI=1toN (1 / LI)
Inductance in series is the sum of the individual inductances.
Four (4) 0.6 Henry inductors connected in series should add up to 2.4 Henry. An electrical event passing through one inductor in time "T" will require "4T" to pass through all four inductors. Hence, inductance adds up in a series of inductors connected end to end.
Inductors in series add up, so 15 mH
When inductors are connected in parallel, the total inductance (L_total) can be calculated using the formula: (\frac{1}{L_{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3}). For the given inductors, this becomes: (\frac{1}{L_{total}} = \frac{1}{0.06} + \frac{1}{0.05} + \frac{1}{0.1}). Calculating this yields (L_{total} \approx 0.017 H) or 17 mH.
Inductance in an electrical circuit.
To find the total inductance ( L_t ) of two inductors in parallel, you can use the formula: [ \frac{1}{L_t} = \frac{1}{L_1} + \frac{1}{L_2} ] For two identical inductors of 22 mH, this simplifies to: [ \frac{1}{L_t} = \frac{1}{22 , \text{mH}} + \frac{1}{22 , \text{mH}} = \frac{2}{22 , \text{mH}} = \frac{1}{11 , \text{mH}} ] Thus, the total inductance ( L_t ) is 11 mH.
Inductors can be used for a great many purposes. Terms, such as 'choke', 'reactor', etc., describe applications of inductors.
Lt= 1/(1/L1+1/L2) Lt= 1/(1/.02+1/.05) Lt= 14.29 mH
actually, inductance is directly proptional to the frequency according to the formula , so if frequency is more, then inductance is also more and vice versa