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assume the following configuration: battery connected to 2 parallel resistors with an ammeter in series with the battery... observe the current measurement ... remove one of the resistors .... observe the current again, it will have decreased: if the resistors were of equal value, the current will decrease to half of its original value when one of the resistors is removed. Mathematics:
V=IR (V- voltage, I - current, R - resistance
in a parallel circuit, R=(R1*R2)/(R1+R2) where R1 and R2 are the values of resistance of the resistors. Before removal- Ib=V*(R1+R2)/(R1*R2)
After removal (assume R2 is removed)- Ia=V/R1
so Ia/Ib=(R1*R2)/(R1*(R1+R2))
or Ia=Ib*(R2/(R1+R2)
if R1=R2 then Ia=Ib*R2/(2*R2) or Ia=Ib/2 so the current after is 1/2 of that before.
What else can I help you with?
What happen to the circuit if there is higher resistance?
In what sense.
When adding more component's why does it reduce the current in a series circuit but that this does not happen in a parallel circuit?
In a series circuit, adding more components increases the total resistance, which reduces the overall current according to Ohm's Law (I = V/R). This is because the same current flows through each component, and additional resistance limits the flow. In contrast, in a parallel circuit, each component provides an alternative path for current, so adding more components decreases the total resistance, allowing more current to flow through the circuit. Thus, while series circuits see a reduction in current with added components, parallel circuits experience an increase.
What will happen if a second bulb is added to a parallel circuit?
-- The voltage doesn't change. -- If the second light bulb is identical to the first, then the total resistance drops by half. -- If they're not identical, then we have to know the details of both before we can calculate their combined effective resistance.
What happen if you change the position of ammeter in the circuit in parallel and series?
-- In a series circuit, no matter where you install the ammeter, it will always read the same current. -- In a parallel circuit, the ammeter may read a different current when it's moved to a different parallel branch.
Why is a parallel circuit used in a household wiring?
In a parallel circuit, if one component gets removed from the circuit, the rest of the components remain undisturbed. If a light bulb burns out in a series circuit, the rest of the components in that circuit will go out with it. But if it were in a parallel circuit, only the light bulb would go out.
What will happen to a buzzer connected to a circuit?
If it is connected in series with a circuit then it might raise the resistance too high and fail the system. Parallel connection is a circuit is probably the best bet you have.
What would happen if a lamp was unscrewed from a parallel circuit?
There will be no change, because it is a parallel circuit.
What would happen to circuit if there was no resistance?
a circuit with no resistance or zero resistance can be considered as open circuit in which the current is zero. without resistance the circuit just becomes open ()
What happen to the circuit if there is higher resistance?
In what sense.
What will happen to voltage in a parallel circuit?
In a parallel circuit the voltage across each component is the same.
What will happen if you undo a bulb in a parallel circuit?
The bulb you remove will go out :) Overall current will also be reduced proportional to the resistance of the bulb being removed. Lets say you have two 60 W incandescent bulbs in parallel and they each are drawing 1/2 Amp (60W = 120 Volts x 1/2 Amp). The resistance of each bulb is 240 Ohms (120 Volts / .5 Amps). The parallel resistance is 120 Ohms so 1 Amp is being drawn. When one of the two bulbs is removed the resistance changes from 120 Ohms to 240 Ohms, reducing the current from 1 Amp to 1/2 Amp.
What would happen if a battery is removed from a circuit?
It wil be on
Which uses more energy parallel circuit or a series circuit?
That depends. For example, if the circuit is consisted of two resistors, 2 ohms each, the equivalent resistance (Req) of these two resistors in series is 4 ohms, and the Req of these two resistors in parallel is 1 ohm. If the same voltage is applied, say 4 V.power consumed in a resistance = V2/R.The parallel circuit: Power = 4 * 4 / 1 = 16 [W].The series circuit: Power = 4 * 4 / 4 = 4 [W].With everything else the same, a parallel circuit consumes more energy than a series circuit.Note that circuits of only simple resistors are discussed. You need to consider each circuit on its merit.================================AnswerIt depends. In both cases, the total energy expended will be the sum of the energies expended by each individual load.
What will happen if ammeter is put across a resistance in a circuit?
Maybe blow the fuse or burn out the wiring. An ammeter has an extremely low resistance. connecting it across the resistance causes the resulting parallel resistance to be slightly lower than the resistance of the ammeter 1/Rt = 1/R + 1/R(ammeter)
What will happen in a circuit if the voltage does not change but the resistance in the circuit increases?
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
What happen when ammeter connected in parallel?
an ideal ammeter has zero or negligible resistance when this is connected in series no effective resistance would be added in the circuit so that the value of curret that we get is exactly of the circuit only. but when the ammeter is connected in parllel as it has zero resistance , the resistor to which it is connected in parllel gets shorted and due to his the effective resistance of the circuit is changed and so the effective current ... due to this the w=value measured by the ammeter would be different (incresed due to dec. in effective resistance)
What is the roll of bleeder resistance in LC filter circuit and what will happen if the bleeder resistor is not used in circuit?
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