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What happens to reactive power in a circuit that has both inductance and capacitance?
Inductors are considered to be a load for reactive power, meaning that they will draw reactive power from the system. Capacitors are considered to be sourced of reactive power, they feed reactive power into the system. If you have a circuit that is at unity (balanced with inductors and capacitors) no reactive power will be drawn from the source. You will have unity power factor. If your circuit is more inductive than capacitive it will be drawing reactive power from the source. The opposite is also true for capacitors.
Explain what happens to current in a purely inductive circuit?
Current in a purely inductive circuit lags the voltage by 90 degrees. The apparent power in such a circuit will be zero, because the power factor is zero, however, energy will still be transferred, and VARs (Volt-Amps-Reactive) will be non-zero.
What would happen if the length of wire increase what happens to the capacitance?
capacitance also increase
What happens in series resonance?
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
What happen when hz is increase?
Your question is rather vague, but what you may be asking is, "What happens in a circuit if the supply frequency is increased?"Well, circuits have some degree of natural resistance, inductance, and capacitance, which may be modified with resistors, inductors, and capacitors. Frequency affects each of these, as follows:Resistance -Resistance is inversely-proportional to a conductor's cross-sectional area. In a DC circuit, charge flow distributes itself across the full cross section of the conductor. However, with AC currents, an effect called 'skin effect' comes into play -this describes the tendency of charge carriers to move closer to the surface of the conductor, essentially reducing the effective cross-sectional area of the conductor, and increasing its resistance. We call this the 'AC resistance' of the conductor; at normal supply frequencies (50/60 Hz) this is insignificant, however it increases significantly with frequency.Inductance -Inductive reactance opposes the flow of AC current, and is directly proportional to the circuit's inductance and to the frequency of the supply. So, as frequency increases, the circuit's inductive reactance increases.Capacitance -Capacitive reactance opposes the flow of AC current, and is inversely proportional to the circuit's capacitance and to the frequency of the supply. So, as the frequency increases, the circuit's capacitive reactance falls.
What happens when inductance is equal capacitance?
Inductance and capacitance are never equal, since they have different units.It's like asking "What happens when temperature is equal to cost ?"It's possible for the inductive and capacitive reactances to be numerically equal,though. That only happens at one frequency, and when it does, your circuit isat resonance.
In a circuit with resistive and inductive load what happens to the power factor as the resistive load increases?
The PF will increase
What happens to reactive power in a circuit that has both inductance and capacitance?
Inductors are considered to be a load for reactive power, meaning that they will draw reactive power from the system. Capacitors are considered to be sourced of reactive power, they feed reactive power into the system. If you have a circuit that is at unity (balanced with inductors and capacitors) no reactive power will be drawn from the source. You will have unity power factor. If your circuit is more inductive than capacitive it will be drawing reactive power from the source. The opposite is also true for capacitors.
Explain what happens to current in a purely inductive circuit?
Current in a purely inductive circuit lags the voltage by 90 degrees. The apparent power in such a circuit will be zero, because the power factor is zero, however, energy will still be transferred, and VARs (Volt-Amps-Reactive) will be non-zero.
What happens if capacitance of circuit is more than resistance?
Resistance is a completely different quantity to capacitance, resistance being measured in ohms and capacitance in farads. So they are 'apples and oranges'. You should be asking, 'What happens if capacitive reactance (in ohms) is larger than resistance?'. And one answer would be that the phase angle will be greater than 45 degrees. There are other answers, too, but it depends what you want to know,
What would happen if the length of wire increase what happens to the capacitance?
capacitance also increase
What happens to the capacitance fi the charge on the plates of a capacitor is doubled?
The capacitance doesn't depend on the charge stored in it. The capacitor has the same capacitance whether it's charged by a DC and just holding it, or in an AC circuit where the charge on it keeps changing and reversing, or in a box on the shelf connected to nothing and not charged at all.
What happens if capacitance is increased in parallel RC ciRCuit and series RC ciRCuit?
In both cases, the time constant of the RC circuit is increased. If the application is a high- or low-pass circuit, then the filter cutoff frequency is decreased in both cases. If the application is a phase-shift network, then the frequency for a given phase- shift is reduced.
What happens in series resonance?
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
What happen when hz is increase?
Your question is rather vague, but what you may be asking is, "What happens in a circuit if the supply frequency is increased?"Well, circuits have some degree of natural resistance, inductance, and capacitance, which may be modified with resistors, inductors, and capacitors. Frequency affects each of these, as follows:Resistance -Resistance is inversely-proportional to a conductor's cross-sectional area. In a DC circuit, charge flow distributes itself across the full cross section of the conductor. However, with AC currents, an effect called 'skin effect' comes into play -this describes the tendency of charge carriers to move closer to the surface of the conductor, essentially reducing the effective cross-sectional area of the conductor, and increasing its resistance. We call this the 'AC resistance' of the conductor; at normal supply frequencies (50/60 Hz) this is insignificant, however it increases significantly with frequency.Inductance -Inductive reactance opposes the flow of AC current, and is directly proportional to the circuit's inductance and to the frequency of the supply. So, as frequency increases, the circuit's inductive reactance increases.Capacitance -Capacitive reactance opposes the flow of AC current, and is inversely proportional to the circuit's capacitance and to the frequency of the supply. So, as the frequency increases, the circuit's capacitive reactance falls.
What happens if you overcompensate with 20mF capacitor for the inductive circuit instead of 10mF capacitor which already satisfy the power factor to reach 0.95?
there would be no problem with this == == The inductive circuit has a 'lagging' power factor. If you over-compensate with too much capacitive reactance, you could go over the top (past 1.0) , and end up with a leading power factor that may even be numerically worse than when you started. == == == ==
Why at resonance the voltage drop across inductance and the voltage drop across capacitance is greater than the source voltage?
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
