The capacitance counter acts the inductivity (decreases it) without impacting the resistivivity, thus increasing the power factor, or resistivity / inductivity ratio.
Inductors are considered to be a load for reactive power, meaning that they will draw reactive power from the system. Capacitors are considered to be sourced of reactive power, they feed reactive power into the system. If you have a circuit that is at unity (balanced with inductors and capacitors) no reactive power will be drawn from the source. You will have unity power factor. If your circuit is more inductive than capacitive it will be drawing reactive power from the source. The opposite is also true for capacitors.
Current in a purely inductive circuit lags the voltage by 90 degrees. The apparent power in such a circuit will be zero, because the power factor is zero, however, energy will still be transferred, and VARs (Volt-Amps-Reactive) will be non-zero.
capacitance also increase
In a DC circuit, if the capacitance value becomes infinite, the capacitor would essentially act as a short circuit after it is fully charged. Initially, it would allow current to flow while charging, but once charged, it would maintain a constant voltage across its terminals and prevent any further current flow. This means that the capacitor would no longer store energy or affect the circuit's operation beyond its initial charging phase.
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
Inductance and capacitance are never equal, since they have different units.It's like asking "What happens when temperature is equal to cost ?"It's possible for the inductive and capacitive reactances to be numerically equal,though. That only happens at one frequency, and when it does, your circuit isat resonance.
The PF will increase
Inductors are considered to be a load for reactive power, meaning that they will draw reactive power from the system. Capacitors are considered to be sourced of reactive power, they feed reactive power into the system. If you have a circuit that is at unity (balanced with inductors and capacitors) no reactive power will be drawn from the source. You will have unity power factor. If your circuit is more inductive than capacitive it will be drawing reactive power from the source. The opposite is also true for capacitors.
Current in a purely inductive circuit lags the voltage by 90 degrees. The apparent power in such a circuit will be zero, because the power factor is zero, however, energy will still be transferred, and VARs (Volt-Amps-Reactive) will be non-zero.
Resistance is a completely different quantity to capacitance, resistance being measured in ohms and capacitance in farads. So they are 'apples and oranges'. You should be asking, 'What happens if capacitive reactance (in ohms) is larger than resistance?'. And one answer would be that the phase angle will be greater than 45 degrees. There are other answers, too, but it depends what you want to know,
capacitance also increase
The capacitance doesn't depend on the charge stored in it. The capacitor has the same capacitance whether it's charged by a DC and just holding it, or in an AC circuit where the charge on it keeps changing and reversing, or in a box on the shelf connected to nothing and not charged at all.
In both cases, the time constant of the RC circuit is increased. If the application is a high- or low-pass circuit, then the filter cutoff frequency is decreased in both cases. If the application is a phase-shift network, then the frequency for a given phase- shift is reduced.
In a DC circuit, if the capacitance value becomes infinite, the capacitor would essentially act as a short circuit after it is fully charged. Initially, it would allow current to flow while charging, but once charged, it would maintain a constant voltage across its terminals and prevent any further current flow. This means that the capacitor would no longer store energy or affect the circuit's operation beyond its initial charging phase.
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
Your question is rather vague, but what you may be asking is, "What happens in a circuit if the supply frequency is increased?"Well, circuits have some degree of natural resistance, inductance, and capacitance, which may be modified with resistors, inductors, and capacitors. Frequency affects each of these, as follows:Resistance -Resistance is inversely-proportional to a conductor's cross-sectional area. In a DC circuit, charge flow distributes itself across the full cross section of the conductor. However, with AC currents, an effect called 'skin effect' comes into play -this describes the tendency of charge carriers to move closer to the surface of the conductor, essentially reducing the effective cross-sectional area of the conductor, and increasing its resistance. We call this the 'AC resistance' of the conductor; at normal supply frequencies (50/60 Hz) this is insignificant, however it increases significantly with frequency.Inductance -Inductive reactance opposes the flow of AC current, and is directly proportional to the circuit's inductance and to the frequency of the supply. So, as frequency increases, the circuit's inductive reactance increases.Capacitance -Capacitive reactance opposes the flow of AC current, and is inversely proportional to the circuit's capacitance and to the frequency of the supply. So, as the frequency increases, the circuit's capacitive reactance falls.
there would be no problem with this == == The inductive circuit has a 'lagging' power factor. If you over-compensate with too much capacitive reactance, you could go over the top (past 1.0) , and end up with a leading power factor that may even be numerically worse than when you started. == == == ==