The PF will increase
current decreases and resistance increases
What happens to the current in a circuit as a capacitor charges depends on the circuit. As a capacitor charges, the voltage drop across it increases. In a typical circuit with a constant voltage source and a resistor charging the capacitor, then the current in the circuit will decrease logarithmically over time as the capacitor charges, with the end result that the current is zero, and the voltage across the capacitor is the same as the voltage source.
The gain increases.
When you close an inductive circuit, since an inductor resists a change in current, the initial reaction of the load is to look like a high resistance. As current builds, the resistance falls. With a theoretical source and inductor, current would eventually reach infinity, that is after infinite time, but practical sources and inductors will reach a plateau current. When you open an inductive circuit, again, since an inductor resists a change in current, the inductor attempts to maintain that current, but there is no conductivity for that current so, the inductor presents a high voltage spike in the reverse direction it was initially "charged" with. With a theoretical inductor, and theoretical infinite impedance, the voltage spike would be infinite. Again, practical inductors have a maximum voltage spike, but this spike can still be quite high, even thousands of volts, which can damage the circuit, so it is important to maintain a conduction path for the collapsing field, often a diode, or a resistor/capacitor filter.
"Ohms Law" defines resistance (R) as the the ratio of voltage (V) to current (I).R = V/IIf you move those variables around, you can get the formula:I = V/RSo you can see that when resistance increases, current flow will decrease.CommentResistance is most definitely not defined as 'the ratio of voltage to current', although that ratio may tell you what it happens to be.Resistance isn't a variable in the Ohm's Law equation. It is a constant because it is unaffected by either current or resistance.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
it increases
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current decreases and resistance increases
it increases
nothing
Increases
Your question needs rephrasing; as it stands, it makes no sense.
The voltage stays the same but the amp hours capacity increases.
when the frequency is increased the total impedance of a series RC circuit is decrease.
Voltage remains constant; current increases.