An improper expression: 2 is an exponent.
P = VI
V = IR
P = (IR)I
P = I^2R
The power dissipated by a resistance ' R ' carrying a current ' I ' is [ I2R ].I2R = (4.5)2 x (3.5) watts = 70.875 joules per second5.5 minutes = (5.5 x 60) = 330 secondsEnergy = (power) x (time) = (70.875) x (330) = 23,388.75 joules
Power dissipated = I2R 0.022 x 1000 = 0.4 watts
Manipulate the following equation, to make I the subject: P = I2R, where P = power, I =current, and R = resistance.
The windings heat up due to I2R power losses and the iron cores heat up due to induced eddy current losses.
With the secondary not supplying any load, there is no secondary current and the primary current will be a low-value magnetising current. So, the copper losses, (I2R) will be insignificant.
Power consumed by a resistance is I2R
The power dissipated by a resistance 'R' carrying a current 'I' is [ I2R ]. The power is dissipated as heat, and you can see from [ I2R ] that for a given current, it's directly proportional to 'R'.
To lower the I2R losses
V2/r=p i2r=p vi=p
to reduce current and the resulting I2R waste of power.
P = I2R Where: P = power loss I = current R = resistance
P=I2R=(59mA)2(8.2kohms)= 28.5443W
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
The relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit is represented by the equation P i2r. This equation shows that power dissipation is directly proportional to the square of the current and the resistance in the circuit.
The power dissipated by a resistance ' R ' carrying a current ' I ' is [ I2R ].I2R = (4.5)2 x (3.5) watts = 70.875 joules per second5.5 minutes = (5.5 x 60) = 330 secondsEnergy = (power) x (time) = (70.875) x (330) = 23,388.75 joules
Due to corona effect virtually conductor size is increase and therefor resistance in transmission line is decreases.so I2R losses will decreases...
V = IR, so an alternate would be P = I2R