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If a current of 4.5 amps flows into a 3.5 ohm resistor for 5.5 minuits the energy dissipated is?
The power dissipated by a resistance ' R ' carrying a current ' I ' is [ I2R ].I2R = (4.5)2 x (3.5) watts = 70.875 joules per second5.5 minutes = (5.5 x 60) = 330 secondsEnergy = (power) x (time) = (70.875) x (330) = 23,388.75 joules
What is the power dissipated by a resistor with a current of 0.02 A adn a resistance of 1000 ohms?
Power dissipated = I2R 0.022 x 1000 = 0.4 watts
Formula used to find the maximum current that can be carried by a resistor if resistance and wattage rating is known?
Manipulate the following equation, to make I the subject: P = I2R, where P = power, I =current, and R = resistance.
Why is it frequently necessary to ventilate alternators by blowing air through them?
The windings heat up due to I2R power losses and the iron cores heat up due to induced eddy current losses.
Why open circuit test show only core losses?
With the secondary not supplying any load, there is no secondary current and the primary current will be a low-value magnetising current. So, the copper losses, (I2R) will be insignificant.
How much heat is created with a resistance?
Power consumed by a resistance is I2R
Why does the heating effect of an electric current depends on the electrical resistance of a conductor?
The power dissipated by a resistance 'R' carrying a current 'I' is [ I2R ]. The power is dissipated as heat, and you can see from [ I2R ] that for a given current, it's directly proportional to 'R'.
Why are high-quality transformers wound with large diameter wire?
To lower the I2R losses
What is formula of power in electronic?
V2/r=p i2r=p vi=p
In long distance overhead lines why voltage increase?
to reduce current and the resulting I2R waste of power.
Formula for power loss in ac cables?
P = I2R Where: P = power loss I = current R = resistance
What is maximum power of a 59ma power and 8.2kohm resistor circuit?
P=I2R=(59mA)2(8.2kohms)= 28.5443W
What is the formula for calculating the power dissipated in a resistor, given the current flowing through it and the resistance value, known as the i2r power?
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
What is the relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit, as represented by the equation P i2r?
The relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit is represented by the equation P i2r. This equation shows that power dissipation is directly proportional to the square of the current and the resistance in the circuit.
If a current of 4.5 amps flows into a 3.5 ohm resistor for 5.5 minuits the energy dissipated is?
The power dissipated by a resistance ' R ' carrying a current ' I ' is [ I2R ].I2R = (4.5)2 x (3.5) watts = 70.875 joules per second5.5 minutes = (5.5 x 60) = 330 secondsEnergy = (power) x (time) = (70.875) x (330) = 23,388.75 joules
What are the Advantages of Corona in transmission lines?
Due to corona effect virtually conductor size is increase and therefor resistance in transmission line is decreases.so I2R losses will decreases...
If P equals IV find an alternate set of units that could also be used to express power?
V = IR, so an alternate would be P = I2R
