0,20kn/m
No.Mass is KgEnergy is Kgm2/s2
To convert from mol/kgm2 to mol/gcm2, you can use the conversion factor 1 kg 1000 g and 1 m2 10000 cm2. Multiply the original value by 1000 and divide by 10000 to get the equivalent value in mol/gcm2.
Joules are the SI unit for energy. One Joule is equal to one kilogram meters squared per seconds squared (kgm2/s2).
Taken from a NASA paper (2010 ASCE Earth & Space, Robotic Lunar Geotechnical Tool);Bearing pressure (kN/m2) = 26.16CBR0.664NOTE: this is only an approximation as there is no real direct correlation between bearing pressure and CBR
Shot putter transfers 245 J of energy to Kinetic energy of steel ball. Kinetic energy, T=(1/2)mv2 must keep track of units however. Joules=Kgm2/s2 So want mass in Kg 7200 g=7.2 Kg So we have: 245 Kgm2/s2=(1/2)*7.2 Kg*v2 v2=68.05 m2/s2 v=8.25 m/s
Don't let them confuse you. Kinetic energy is 1/2 mv2. His time of acceleration and the force acting on him are irrelevent. k = mv2/2 k = 100kg * (12m/s)2/2 =14400 kgm2/s2/2 =7200kgm2/s2 k = 7200N
The torque from the force, T = r X F = .2m*40N*sin(90o) = 8Nm.The angular acceleration, A = (w-0)/t = 10/4 = 2.5rad/s2.As, T = IA,then I = T/A,so I = 8Nm/2.5rad/s2. = 3.2 kgm2.
you can measure the force between two objects (force and reaction) using the following equation:.f = (( G * m1 * m2 ) / d ^2).example: 100 kg mass at earths surface.key:G = 6.672 * 10 ^-11 (newtons gravitational constant)m1 = mass 1 = 100 kgm2 = mass 2 = 5.974 * 10 ^24 kg (earths mass)d = 6 371 000 metres (earths radius).f = 982 newtons
The gravitational attraction between two masses isF = G M1 M2/R2For this exercise,M1 = 8 kgM2 = 4 kgR = 0.5 km = 500 metersand 'G' is the universal gravitational constant, G = 6.67 x 10-11F = (6.67 x 10-11) (8)x(4)/(500)2 = 8.5376 x 10-15 = 0.000 000 000 000 0085376 newtonThat's about 3.071 x 10-14 ounce (0.000 000 000 000 03071 ounce)
Energy units. There are a number of these. The SI energy unit is the Joule, but in some contexts you might see energy expressed in kilowatt-hours, ergs, foot-pounds, therms, Hartrees, electron-volts, calories, or BTUs.
As per the eqn E=h( new) where (new) is the frequency component, it is directly related to energy and power. As frequency increases the power level of the signal increases and hence high frequency signal is used in long distance transmissions.
Assume the centers of mass of the cars are 25m apart :F = G m1m2 / R2G = 6.673 x 10-11F = (6.673 x 10-11) (1,000)(1,000)/(25)2 = 0.0000001068 newton (rounded)(about 0.000000384 ounce)