#include<iostream>
#include<vector>
int main()
{
std::vector<int> Array;
Array.push_back (42); // insert
Array.pop_back(); // delete
}
Using sorted(array,reverse=True)
Start by pointing to each end of the array. Work your way towards the middle of the array, swapping elements as you go. When the pointers meet or pass each other, the array is completely reversed.
To write a C++ program to display the student details using class and array of object.
The simplest way is probably to read the numbers into an array and then prints each element of the array starting at the last one and moving backwards.
An array of order 4x8 can either be implemented as a one-dimensional array of order 32 or as a one-dimensional array of order 4, where each element is a one-dimensional array of order 8. In either case, the 32 data elements are allocated contiguously and there is no difference in performance. A third way is to implement the one-dimensional array of order 4 as an array of pointers to separately allocated one-dimensional arrays of order 8. The order 4 array is contiguous as are the order 8 arrays, however they need not be contiguous with one another other. This is the least efficient implementation due to the additional level of indirection required to navigate the array.
Using sorted(array,reverse=True)
Start by pointing to each end of the array. Work your way towards the middle of the array, swapping elements as you go. When the pointers meet or pass each other, the array is completely reversed.
sorry
The best-case time complexity of the Bubble Sort algorithm is O(n), where n is the number of elements in the array. This occurs when the array is already sorted. The worst-case time complexity is O(n2), which happens when the array is sorted in reverse order.
To write a C++ program to display the student details using class and array of object.
To find the median of an array of numbers, first, arrange the numbers in ascending order. If the array has an odd number of elements, the median is the middle number. If the array has an even number of elements, the median is the average of the two middle numbers.
import java.util.Arrays; public class arraysort { public static void main(String[] a) { int array[] = { 2, 5, -2, 6, -3 }; Arrays.sort(array); for (int i : array) { System.out.println(i); } } }
The simplest way is probably to read the numbers into an array and then prints each element of the array starting at the last one and moving backwards.
To find the kth smallest number in an unsorted array, you can use a sorting algorithm like quicksort or heapsort to arrange the array in ascending order. Then, you can simply access the kth element in the sorted array to find the kth smallest number. This process ensures that the kth smallest number is easily identified and retrieved from the array.
The number is 21978. 21978 when multiplied by 4 which gives the result 87912 which is in reverse order.
#include "stdio.h" #define ARRAY_SIZE 10 void fill(float* array, int size); void spill(float* array, int size, char* delimiter); void bubble_sort(float* array, int size); void reverse(float* array, int size); void swap(float* a, float* b); int main(int argc, char* argv[]) { float numbers[ARRAY_SIZE]; fill(numbers, ARRAY_SIZE); bubble_sort(numbers, ARRAY_SIZE); spill(numbers, ARRAY_SIZE, " "); reverse(numbers, ARRAY_SIZE); spill(numbers, ARRAY_SIZE, " "); return 0; } void fill(float* array, int size) { int i = 0; while (i < size) fscanf(stdin, "%f", array + (i++)); } void spill(float* array, int size, char* delimiter) { int i = 0; while (i < size) fprintf(stdout, "%f%s", array[i++], delimiter); fputc('\n', stdout); } void bubble_sort(float* array, int size) { int i, j; for (i = 0; i < size; i++) for (j = i; j < size; j++) if (array[i] > array[j]) swap(array + i, array + j); } void reverse(float* array, int size) { int i; for (i = size / 2; i >= 0; i--) swap(array + i, array + (size - (i + 1))); } void swap(float* a, float* b) { float c = *a; *a = *b; *b = c; } fill gets the numbers from input spill sends them to output bubble sort will sort the array in ascending order reverse will reverse the list so that it is in descending order swap is used to swap two floats You can change float to double or int depending on which datatype you want to use.
plz as soon as possible give me the program for shorting an array in asscending order without using any sort function in c++