What is a c program to reverse a five digit number?

Answer 1

#include <stdio.h>

int main(void){

// Local Declerations

int intNum;

int midDigit;

// Statements

printf("Enter a 5 digit integral number: ");

scanf("%d", &intNum);

//the assignment expression below is used to calculate the mid digit

oneDigit = (intNum % 1000) / 100;

printf("\nThe middle digit is: %d", oneDigit);

return 0;

}

Answer 2

// Returns the sum of the left-most and right-most digits of num.

// If num contains only one digit, returns num.

unsigned int getSum(const unsigned int num) {

// Special case for single-digit numbers.

if(num <= 9) {

return num;

}

// We can find the right-most digit of num by modding it by 10.

const unsigned int rightmostDigit = num % 10;

// We can find the left-most digit of num by dividing it by 10^(numDigits-1)

const unsigned int numDigits = getNumDigits(num);

const unsigned int p = (unsigned int) pow(10.0, numDigits - 1);

const unsigned int leftmostDigit = num / p;

return rightmostDigit + leftmostDigit;

}

// Returns the number of digits in n

unsigned int getNumDigits(const unsigned int n) {

return ((unsigned int) log10(n) + 1);

}

Answer 3

#include

int main()
{
int original;
int original_backup;
int backward=0;

do
{
printf("Enter a five digit number, please!");
scanf("%d",&original);

}
while (original>99999 original < 10000);
/*this loop will ask for a new number as long as the user doesn't provide a five-digit one*/
/*note that if you remove it, the program will actually work for any number of digits*/

original_backup = original; /*this will remember the original number for later, as we will destroy it in the process*/

while(original) /*this loop actually turns it around (it will go as long as original is not zero*/
{
backward = backward * 10; /*shift the new number one place to the left and add a zero to the end*/
backward = backward + (original % 10); /* so we can add the last digit of the original number*/
original = original / 10; /*and delete it, so the loop actually checks four-digit number in the next iteration (and three-, two-, one-, zero-digit after that)*/

}

if(backward == original_backup) puts("The number is a palindrome.");
else printf("%d",backward);
return 0;

}

Answer 4

#include <iostream>

#include <string>

using std::cin;

using std::cout;

using std::endl;

using std::string;

int main()

{

const int numberOfDig = 5;

string num = "0";

cout << endl << "Enter a five digit number: ";

cin >> num;

string revNum = "00000";

for (int i = 0; i < numberOfDig; i++)

{

revNum[numberOfDig - i - 1] = num[i];

}

cout << endl << "You have entered: " << num

<< endl << "Reversed number is: " << revNum

<< endl;

system("PAUSE");

return 0;

}

OR a much simpler (not perfect) newbie method would be

#include<stdio.h>

#include<conio.h>

int main()

{

clrscr();

int a,b,c,d,e,f,g,i,h;

printf("enter a number");

//i supposed tht given numbers are vwxyz

scanf("%d",&a); //vwxyz

b=a/10000; //v

c=a%10000; //wxyz

d=c/1000; //w

e=c%1000; //xyz

f=e/100; //x

g=e%100; //yz

h=g/10; //y

i=g%10; //z

printf("reversed stuff is %d%d%d%d%d",i,h,f,d,b); //output is zyxwv

getch();

}