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How could a capacitor have voltage but no current?
Voltage and current are two different things. Voltage is potential energy per charge, in joules per coulomb, while current is charge transfer rate, in coulombs per second. Its that same as saying that a battery has voltage but no current, because there is no load. Well, a capacitor resists a change in voltage by requiring a current to change the voltage. Once that voltage is achieved, there is infinite resistance to the voltage, and thus no current.
What is ramp voltage?
Ramp voltage is a voltage that can be steadily increasing or decreasing.
How to generate a voltage in a coil?
The voltage induced into a coil is proportional to the rate of change of current (dI/dt) through that coil. If the current is a constant value, then no voltage is induced. The equation is as follows: V = - L (dI/dt)where L is the inductance of the coil, measured in henrys, and dI/dt means 'change of current divided by change of time'. The minus sign indicates that the induced voltage opposes the change in current.
How you can change a constant DC voltage to a variable DC voltage?
By installing the varialble resistor in the circuit,the constant dc voltage would change .
What is Faraday's law?
Overall, induced voltage is proportional to the product of the number of loops of coiled wire and the rate at which the magnetic field changes
What is edge speed in electronics?
A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line. A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line.
How is slew rate affect on amplifier?
as it is rate of change of output voltage..so it affect amplifier output
What is slew rate?
slew rate is the ability of an amplifier to reproduce amplified version of the input signal in terms of frequency and phase. The input signal amplitude change is fast. But the amplifier will take some time to give response to the changes in input signal. i.e. how fast the amplifier tracks the input signal is the slew rate. For an amplifier the slew rate should be high in order to avoid signal distortion. The rate of change of the output voltage of an amplifier for the given input signal change is called the slew rate.
Which law states that voltage is induced in a circuit whenever the flux linking the circuit is changing and that the magnitude of the voltage is proportional to the rate of change of the flux linkage?
Faraday's law of electromagnetic induction states that a voltage is induced in a circuit whenever there is a changing magnetic field that links the circuit, and the magnitude of the induced voltage is proportional to the rate of change of the magnetic flux.
Why must the instantaneous current wave be exact 90 degree out-of phase with the applied voltage waveform across an ideal inductor?
Because the voltage induced is proportional to the rate of change of current, and the maximum rate of change of current occurs at the point where the current waveform is 'steepest' -i.e. as it passes through zero. So, as the current passes through zero, the corresponding value of induced voltage is maximum, which means the voltage and current waveforms are displaced by a quarter of the wavelength, or 90 degrees.
What does the rate of change of flux equal?
The rate of change of flux equals the induced electromotive force or voltage in a circuit, as described by Faraday's law of electromagnetic induction. Mathematically, this relationship is expressed as: (\text{EMF} = -\frac{d\Phi}{dt}), where EMF is the induced voltage, (\Phi) is the magnetic flux, and (\frac{d\Phi}{dt}) is the rate of change of magnetic flux over time.
What is the relationship between the current in an LC circuit and the voltage across its components?
In an LC circuit, the current and voltage are related by the equation V L(di/dt) Q/C, where V is the voltage across the components, L is the inductance, C is the capacitance, Q is the charge, and di/dt is the rate of change of current. The current in the circuit is directly proportional to the rate of change of voltage across the components.
What is the relationship between capacitor current and voltage in an electrical circuit?
The relationship between capacitor current and voltage in an electrical circuit is that the current through a capacitor is directly proportional to the rate of change of voltage across it. This means that when the voltage across a capacitor changes, a current flows to either charge or discharge the capacitor. The relationship is described by the equation I C dV/dt, where I is the current, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
How does the voltage across a capacitor change over time when a current is flowing through it?
When a current flows through a capacitor, the voltage across it increases or decreases depending on the rate of change of the current. If the current is constant, the voltage remains steady. If the current changes rapidly, the voltage across the capacitor changes quickly as well.
How could a capacitor have voltage but no current?
Voltage and current are two different things. Voltage is potential energy per charge, in joules per coulomb, while current is charge transfer rate, in coulombs per second. Its that same as saying that a battery has voltage but no current, because there is no load. Well, a capacitor resists a change in voltage by requiring a current to change the voltage. Once that voltage is achieved, there is infinite resistance to the voltage, and thus no current.
How many volts equals 50Hz?
Voltage is a measure of potential difference while Hertz is the term we use for cycles per second when we consider rates of change. We might say 50 Hz is a rate of change of voltage equal to 50 cycles of that voltage per second. There isn't a way to "convert" voltage to Hertz.
What ıs capacitance?
Capacitance is resistance (not ohms) to a change in voltage using stored charge. The differential equation of a capacitor is dv/dt = i/c. This means that the rate of change of voltage is directly proportional to current and inversely proportional to capacitance.
