You can use any development system, C or otherwise, to write a text editor. The tool to create one, however, depends upon which environment you want it used under (command-line or graphical).
Assuming you're using the Win32API in one form or another, the CreateWindow() function can be used to create a multiline edit control using the following call:
hwndEdit = CreateWindowEx(0, L"EDIT", NULL,
WS_CHILD|WS_VISIBLE|WS_VSCROLL|ES_LEFT|
ES_MULTILINE|ES_AUTOVSCROLL,
x, y, width, height, hwndParent, 0, hInstance, NULL);
This gives you a control with some basic capabilities. Just supply the desired x,y location as well as the width and height. hwndParent is the parent window, and hInstance is the instance your program was given through the WinMain() entry point.
If you're using a modern IDE that allows you to generate forms, you can create a program fairly quickly. Keep in mind that most modern text editors include the following controls:
- a multiline edit box
- main menu (File, Edit, and sometimes Options and Help)
- convenient buttons below the main menu for file and edit operations
Clipboard operations such as copy, cut and paste are also common among text editors. These functions allow you to export and import text data from and to other programs as well as within the text editor.
As with any programming project, start out with the basics and keep adding features you want in the program. Always be sure to conduct bug testing regularly, particularly when you're loading and saving files. Using Notepad as a frame of reference for laying out your controls can come in handy. You may also find some C source code for text editors and base your own on that code.
printf("%c[%d;%dmHello World%c[%dm\n",27,1,33,27,0);
C# EXAMPLEString text="My sample data";System.Text.ASCIIEncoding encode=new System.Text.ASCIIEncoding();//convert to binary and store in a byte[]byte[] binaryArray=encode.GetBytes(text);
Where from? Where to? Be more specific.
Place the text between /* */ .
C. Tags
worldpad are text editer that are included with the window perating system.
To solve the problem (7\text{c} , 3\text{fl oz} - 3\text{c} , 4\text{fl oz}), first convert the measurements to a common unit. This can be done by converting the fluid ounces into cups (since 1 cup = 8 fl oz): (3 \text{ fl oz} = \frac{3}{8} \text{c}) and (4 \text{ fl oz} = \frac{4}{8} \text{c} = \frac{1}{2} \text{c}). Now, the equation becomes (7\text{c} + \frac{3}{8}\text{c} - 3\text{c} - \frac{1}{2}\text{c}). Combining these gives (4\text{c} + \frac{3}{8}\text{c} - \frac{4}{8}\text{c} = 4\text{c} - \frac{1}{8}\text{c} = \frac{32}{8}\text{c} - \frac{1}{8}\text{c} = \frac{31}{8}\text{c}), resulting in (3 \text{c} , 7.5 \text{fl oz}) after converting back to cups and fluid ounces.
Butthead the goat
i dont know the answer i was asking you
To calculate the final concentration of a solution, you can use the formula: [ \text{C}_1 \times \text{V}_1 = \text{C}_2 \times \text{V}_2 ] where ( \text{C}_1 ) is the initial concentration, ( \text{V}_1 ) is the initial volume, ( \text{C}_2 ) is the final concentration, and ( \text{V}_2 ) is the final volume. If you know the initial concentration and volume and the final volume, you can rearrange the formula to solve for ( \text{C}_2 ): [ \text{C}_2 = \frac{\text{C}_1 \times \text{V}_1}{\text{V}_2} ].
Film editing by:Neeraj Voralia
printf("%c[%d;%dmHello World%c[%dm\n",27,1,33,27,0);
To calculate the calories required to heat 863 g of water from 19°C to 88°C, you can use the formula: [ \text{Calories} = \text{mass (g)} \times \text{specific heat (cal/g°C)} \times \text{temperature change (°C)} ] The specific heat of water is approximately 1 cal/g°C. The temperature change is (88°C - 19°C = 69°C). Thus, the calculation is: [ 863 , \text{g} \times 1 , \text{cal/g°C} \times 69 , \text{°C} = 59,607 , \text{calories} ] Therefore, 59,607 calories are required to heat the water.
The conversion of ethylbenzene to phenylethene involves the elimination of hydrogen gas (dehydrogenation) from ethylbenzene. The reaction can be represented by the equation: [ \text{C}_6\text{H}_5\text{C}_2\text{H}_5 \rightarrow \text{C}_6\text{H}_5\text{C}_2\text{H} + \text{H}_2 ] In this equation, ethylbenzene (C6H5C2H5) is converted to phenylethene (C6H5C2H) by removing a hydrogen molecule (H2).
In the given reaction, ( \text{C}5\text{H}{12} ) is converted to ( \text{C}_5\text{H}_8 ) with the production of ( 2 , \text{H}_2 ). The balanced equation shows that 1 mole of ( \text{C}5\text{H}{12} ) produces 2 moles of ( \text{H}_2 ). Therefore, the mole ratio of ( \text{C}5\text{H}{12} ) to ( \text{H}_2 ) is 1:2.
Same as English, c.
Ctrl+C copys the selected text, to paste press Ctrl+V.