You need to mention whether the resistors are in series or parallel to get the right answer
To find the voltage drop across a relay, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). In this case, the current is 0.0015 amps and the resistance is 12,000 ohms. Therefore, the voltage drop can be calculated as V = I × R = 0.0015 A × 12,000 Ω = 18 volts. Thus, the voltage drop across the relay is 18 volts.
Ohm's Law requires you know two of three parameters to calculate the third. Volts = Amps x Ohms You need to know current flowing through resistance to calculate voltage drop.
If the voltage is 500 volts, and the power is 200 kilo-watts, then the current is 400 amperes. (Watts equals Volts time Amperes)The resistance of the conductor has nothing to do with this calculation, but that fact that the conductors are 0.1 ohms means that the voltage drop across each conductor is 40 volts. (Volts equals Amperes times Ohms) Since there are two conductors, the total voltage drop is 80 volts, and the voltage available to the load will be 420 volts.
Doing it with a single resistor is not a good idea because it can only be done with exactly the right amount of current. If the current is 1 amp, for a voltage drop of 10.8 volts you need 10.8 ohms (volts/amps).
R = voltage drop divided by current 13-6 = 7 volts, 7/1 is 7 ohms. If you have a device that has inrush (e.g., a motor or coil) you could have short-lived spikes well over triple the current, making it likely the voltage will drop during startup, which could damage the device. Personally, I would use a voltage divider to remove current from the equation: R2 = R1/ (v.in/v.out - 1) 0.86 x R2 = R1 (e.g., R2 is 1000 ohms and R1 is 860 ohms)
12 volts
To find the voltage drop across a relay, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). In this case, the current is 0.0015 amps and the resistance is 12,000 ohms. Therefore, the voltage drop can be calculated as V = I × R = 0.0015 A × 12,000 Ω = 18 volts. Thus, the voltage drop across the relay is 18 volts.
Ohm's Law requires you know two of three parameters to calculate the third. Volts = Amps x Ohms You need to know current flowing through resistance to calculate voltage drop.
1.36 volts Ohm's Law: Volts = Amps * Ohms
If the voltage is 500 volts, and the power is 200 kilo-watts, then the current is 400 amperes. (Watts equals Volts time Amperes)The resistance of the conductor has nothing to do with this calculation, but that fact that the conductors are 0.1 ohms means that the voltage drop across each conductor is 40 volts. (Volts equals Amperes times Ohms) Since there are two conductors, the total voltage drop is 80 volts, and the voltage available to the load will be 420 volts.
V=R I then, V = 10 + 8 = 18V, R=2Ohm, I=V/R=18/2=9A
Ohms are the unit of resistance you find in Ohms LAw which says Volts = Amps x Ohms. You can get a voltage drop across a resistance, but would have to know what current is being used and you would have a potentiometer in effect. You are not "converting 12V" to 10V, your are essentially loosing two volts through a resistor.
Doing it with a single resistor is not a good idea because it can only be done with exactly the right amount of current. If the current is 1 amp, for a voltage drop of 10.8 volts you need 10.8 ohms (volts/amps).
A resistor in parallel with a voltages source will not cause the voltage to drop, theoretically. To get a 20 volt drop you need a resistance in series, and the number of ohms is 20 divided by the current in amps. If the current is unknown or variable, the voltage can't be dropped by using a resistor.
Don't follow what a '2200watt resistor' is. A resistor spec is measured in ohms. Ohms Law is expressed as: Voltage drop = current x resistance, and the wattage of the resistor is = volts drop x current. You have to decide if your resistor is 2200 ohms, or is taking 2200 watts. These two alternatives will give different results for the current. If it is 2200 watts, at 110 volts, the current is 20 amps. If it is 2200 ohms, at 110 volts, the current will be 50 milliamps. (0.05amps)
Voltage drop is the decrease in electrical potential energy of electrons as they move through a circuit due to resistance. When electrons encounter resistance, they transfer some of their energy to overcome it, resulting in a decrease in voltage along the circuit. This drop in voltage is proportional to the resistance in the circuit and can affect the performance of electrical components.
Google Ohms Law. It will give you all the formulas you need to compute Ohms,Volts and Amps. Simple formulas :-)