as far as i know u have 4 cases for the node u wanna delete
1.It's a leaf (has no children)
2.It has only left child
3.it has only right child
4.it has both children ,left and right
now, let's work on it :>
set a pointer node to the root
while the element to be deleted doesnt equal the pointer
if it's smaller, move the pointer to the left subtree
if it's large , move the pointer to the right subtree
if pointer reached the end of the tree , null, break the loop (unluckly that means u didnt find the element that should be removed)
end while //(now u must have found the target, the while condition is breaked normally)
// this is case 4
if both children don't equal null
get the most left node in the subtree of the pointer node
assign its value to the pointer node.
remove it (set that most left thing to equal null)
//...case 2
if pointer node.right only equals null
pointer node = pointer node.left
//...case3
if pointer node.left only equals null
pointer node = pointer node.right
//... case 1
if pointer node.left and .right equals null
pointer node.data = null
maybe it doesnt look like any algorithm style ,sorry for that, that's as far as i knw, i doubt case 4 anyways..
Given a list and a node to delete, use the following algorithm: // Are we deleting the head node? if (node == list.head) { // Yes -- assign its next node as the new head list.head = node.next } else // The node is not the head node { // Point to the head node prev = list.head // Traverse the list to locate the node that comes immediately before the one we want to delete while (prev.next != node) { prev = prev.next; } end while // Assign the node's next node to the previous node's next node prev.next = node.next; } end if // Before deleting the node, reset its next node node.next = null; // Now delete the node. delete node;
Use a recursive function. void delete_node (node* n) { /* ensure the given pointer is valid */ if (n==NULL) return; /* recursively delete the left child */ delete_node (n->left); n->left = NULL; /* recursively delete the right child */ delete_node (n->right); n->right = NULL; /* delete the data (assuming the data is a pointer)*/ free (n->data); n->data = NULL; /* finally, delete the node itself */ free (n); n=NULL; }
Since a binary search tree is ordered to start with, to find the largest node simply traverse the tree from the root, choosing only the right node (assuming right is greater and left is less) until you reach a node with no right node. You will then be at the largest node.for (node=root; node!= NULL&&node->right != NULL; node=node->right);This loop will do this. There is no body because all the work is done in the control expressions.
In programming, a parent node is any node that holds some reference to a child node. The child node may itself be a parent node. A classic example of parent/child node usage is the binary tree, where every node in the tree may hold a reference to up to 2 children. Nodes that have no children are known as leaf nodes.
There are three primary cases to consider when deleting a node from a binary search tree (BST): Leaf Node: If the node is a leaf (has no children), it can simply be removed. Single Child: If the node has one child, it can be removed, and its child can take its place. Two Children: If the node has two children, it is typically replaced with its in-order predecessor (maximum value in the left subtree) or in-order successor (minimum value in the right subtree), followed by deleting the predecessor or successor node.
The process of implementing the heap delete algorithm involves removing the root node from the heap, replacing it with the last node, and then reorganizing the heap to maintain the heap property. This typically involves comparing the node with its children and swapping it with the larger child if necessary, repeating this process until the heap property is restored.
To insert a new node at the root position in a binary search tree, the tree must be restructured by following these steps: Create a new node with the desired value. Compare the value of the new node with the value of the current root node. If the new node's value is less than the root node's value, set the left child of the root node to be the current root node, and set the left child of the new node to be the previous left child of the root node. If the new node's value is greater than the root node's value, set the right child of the root node to be the current root node, and set the right child of the new node to be the previous right child of the root node. Set the new node as the new root of the binary search tree. By following these steps, a new node can be inserted at the root position of a binary search tree while maintaining the binary search tree properties.
Traversing a binary tree in a depth-first manner using the depth-first search algorithm involves visiting each node's children before moving on to the next level. This is done by starting at the root node, then recursively visiting the left child, then the right child, and continuing this pattern until all nodes have been visited.
A binary tree is a type of tree data structure in which each node has at most two children. To convert a tree to a binary tree, we can follow these steps: Choose a root node for the binary tree. This will be the node at the top of the tree, and all other nodes will be connected to it. For each child node of the root node, add it as a left or right child of the root node, depending on its position relative to the root node. For each child node of the root node, repeat step 2 for its child nodes, adding them as left or right children of the appropriate parent node.
Binary tree insertion involves adding a new node to a binary tree while maintaining the tree's structure. The key steps in inserting a new node are: Start at the root node and compare the value of the new node with the current node. If the new node's value is less than the current node, move to the left child node. If it is greater, move to the right child node. Repeat this process until reaching a leaf node (a node with no children). Insert the new node as the left or right child of the leaf node, depending on its value compared to the leaf node's value.
Given a list and a node to delete, use the following algorithm: // Are we deleting the head node? if (node == list.head) { // Yes -- assign its next node as the new head list.head = node.next } else // The node is not the head node { // Point to the head node prev = list.head // Traverse the list to locate the node that comes immediately before the one we want to delete while (prev.next != node) { prev = prev.next; } end while // Assign the node's next node to the previous node's next node prev.next = node.next; } end if // Before deleting the node, reset its next node node.next = null; // Now delete the node. delete node;
Use a recursive function. void delete_node (node* n) { /* ensure the given pointer is valid */ if (n==NULL) return; /* recursively delete the left child */ delete_node (n->left); n->left = NULL; /* recursively delete the right child */ delete_node (n->right); n->right = NULL; /* delete the data (assuming the data is a pointer)*/ free (n->data); n->data = NULL; /* finally, delete the node itself */ free (n); n=NULL; }
To delete an node in a linked list...If the head node is empty, stop, and return failed.Interate thorugh each member of the list.Remember at each iteration, the address of the privious node.If the current node is the head node or not the desired node, continue to the next iteration.Move the current node's pointer value to the previous node's pointer.Delete the current node, and return success.Return failed..
Since a binary search tree is ordered to start with, to find the largest node simply traverse the tree from the root, choosing only the right node (assuming right is greater and left is less) until you reach a node with no right node. You will then be at the largest node.for (node=root; node!= NULL&&node->right != NULL; node=node->right);This loop will do this. There is no body because all the work is done in the control expressions.
In programming, a parent node is any node that holds some reference to a child node. The child node may itself be a parent node. A classic example of parent/child node usage is the binary tree, where every node in the tree may hold a reference to up to 2 children. Nodes that have no children are known as leaf nodes.
A heap is a complete binary tree where each node has a value greater than or equal to its children (max heap) or less than or equal to its children (min heap). A binary search tree is a binary tree where the left child of a node has a value less than the node and the right child has a value greater than the node. The key difference is that a heap does not have a specific order between parent and child nodes, while a binary search tree maintains a specific order for efficient searching.
There are three primary cases to consider when deleting a node from a binary search tree (BST): Leaf Node: If the node is a leaf (has no children), it can simply be removed. Single Child: If the node has one child, it can be removed, and its child can take its place. Two Children: If the node has two children, it is typically replaced with its in-order predecessor (maximum value in the left subtree) or in-order successor (minimum value in the right subtree), followed by deleting the predecessor or successor node.