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The formula you are looking for is I = kW x 1000/1.73 x E x pf. I = 1.5 x 1000 = 1500. 1500/1.73 x 400 x .86 = 1500/595 = 2.5 amps.

A standard motor's efficiency between 5 to 100 HP is .84 to .91.

A standard motor's power factor between 10 to 100 HP is .86 to .92.

A feeder for a motor has to be rated at 125% of the motors full load amps 2.5 x 125% = 3.1 amps

A #14 copper conductor with an insulation rating of 90 degrees C is rated at 15 amps.

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