Current in 200kw at 480 volts = 200,000/480 = 416.667 amps
This question cannot be answered as asked. you would need to know also the voltage and phasing. Assuming we are dealing with 120-volt, single phase, 11,500 watts would be 55-running amps. Assuming we are dealing 208-volts, three phase, 11,500 watts would be 32 running amps and assuming we are dealing with 250-volt three phase, 11,500 watts would be 26.5 running amps. I hope I have answered your question.
250 kW= 250,000 watts1 horsepower=746 watts (The motor is approx. 335 horsepower. (just FYI))The Ohm's Law formula for this is:P(Power in watts)=I(Current in amps) x E(Voltage)Since the voltage is unknown, I will give you different options based on input voltage.I will assume three phase power for a motor this size.So, back to the formula:250,000=I x ELet's assume voltage (E) to be 480v:250,000=I x 480I=520 ampsFor a voltage of 208 (much less likely for this size motor):250,000=I x 208I=1201 ampsThese are 'running' currents only. The amount of starting current will be much, much higher, but only for a brief period.AnswerThe above answer assumes that the motor's input power is 250 kW. But this is not the case.The power of a motor is always expressed in terms of its output power, not its input power! In North America, this is expressed in horse power, whereas everywhere else it's expressed in watts. So, to determine the current drawn by the motor, you have to start by determining its input power (input power is output power times efficiency); if you don't have a means of determining the motor's efficiency, then you cannot really find out its input power, in which case, you cannot find its current.
For cables in 'Free Air', that is, not routed through conduit, it depends on the Temperature rating of the cable; 60 deg C: 40 amps, 75 deg C: 50 amps, 90 deg C: 55 amps As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.Before you do any work yourself,on electrical circuits, equipment or appliances,always use a test meter to ensure the circuit is, in fact, de-energized.IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS.
At 2965 rpm it sounds like an induction motor for a 50 Hz supply. A 45 kW motor would draw about 55 kW from the supply with a power factor of 0.85, so that is 65 kVA, and on a 415 v 3-phase supply that is a current of 90 amps. For armoured XLPE cale the size needed is at least 16 mm2 Probably 25 mm2 would be preferred for a permanent installation but it would depend on how the cable is installed, how much free air movement there is around it etc.
75 HP = 55 KW 55 = 31/2 x 0.220 x I x cos φ = 31/2 x 0.220 x 0.8 x I I = 55/(31/2 x 0.220 x 0.8) = 180,42 A 3 x 70 mm2 is the size of cable for 75 HP 220 Volts 3 phase motor
55/12=4.6
This question cannot be answered as asked. you would need to know also the voltage and phasing. Assuming we are dealing with 120-volt, single phase, 11,500 watts would be 55-running amps. Assuming we are dealing 208-volts, three phase, 11,500 watts would be 32 running amps and assuming we are dealing with 250-volt three phase, 11,500 watts would be 26.5 running amps. I hope I have answered your question.
5.5% of 480= 5.5% * 480= 0.055 * 480= 26.4
317.025280 KILOWATTS = 317,025.28 WATTS
The formula you are looking for is I = KVA x 1000/1.73 x E, I = 35 x 1000 = 35000/1.73 x 220 = 381, 35000/381 = 92 amps on the primary side. 35000/1.73 x 480 = 830, 35000/830 = 42 amps on the secondary. Transformer conductors need to be rated at 125% so the primary will need an ampacity of 92 x 125% = 115. A #3 copper conductor with an insulation factor of 90 degrees C is rated at 115 amps. The secondary conductors will need an ampacity of 42 x 125% = 53 amps A #8 copper conductor with an insulation factor of 90 degrees C is rated at 55 amps.
A sauna heating element is a resistive load. The equation that you are looking for is Amps = Watts/Volts = 8000/220 = 36 amps. A #8 copper conductor with an insulation rating of 90 degrees C is rated at 55 amps. This will be fed with 40 amp two pole breaker.
To keep costs down, by special permission in the electrical code, for home wiring on a 120/240 volt system 2/0 is allowed. For any other type 200 amp service 3/0 that has a insulation factor of 75 or 90 degrees C is rate at 200 and 225 amps respectively.
The ampacity of a # 10 copper wire with an insulation factor of 90 degrees C is 30 amps. All wire voltage ratings usually drop into two categories 300 volts and 600 volts. Home wiring drops into the 300 volt range and commercial, industrial, drops into the 600 volt range.
It is going about 8.73 km/sec or 31418.2 kph (19522.35 mph). 480/55 = 8.7272 8.7272 x 3600 sec/hr = 31418.18
440 as it is the number that is halfway between them, or half of their total.
yes my honda phantom has 12v 55 watt headlight
AWG # 6 copper