By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.
The voltage is greater than the applied voltage, why?
Ohm's law states that the current in a circuit is inversely proportional to the circuit resistance. There is a single path for current in a series circuit. The amount of current is determined by the total resistance of the circuit and the applied voltage.
Amps Ohm's law states the current is directly proportional to the applied emf (voltage) and inversely proportional to the resistance of the circuit.
no
.2A
Correct Answer= "the current will increase"
POWER, P=V*Iif, P=10w,I=5AP=>10W = V * 510=5VV=2volts
The relationship between current and voltage in an electrical circuit is described by Ohm's Law, which states that the current flowing through a circuit is directly proportional to the voltage applied across it, and inversely proportional to the resistance of the circuit. In simpler terms, as the voltage increases, the current flowing through the circuit also increases, assuming the resistance remains constant.
The relationship between voltage and current in an electrical circuit is described by Ohm's Law, which states that the current flowing through a circuit is directly proportional to the voltage applied across it, and inversely proportional to the resistance of the circuit. This means that as the voltage increases, the current flowing through the circuit also increases, assuming the resistance remains constant.
Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".
For a series circuit, the applied voltage equals the sum of the voltage drops
this is the amount of voltage a circuit can hold.
The relationship between the voltage applied to a circuit and the velocity of electrons within that circuit is direct. When a higher voltage is applied to a circuit, the electrons within the circuit move faster, resulting in an increase in their velocity.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
The applied voltage is 53+28 = 81V.
By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.