i think 15
well , reinforcement steel required for slab is nearly 0.7 to 0.8% of the volume of concrete so if concrete is 1 cum then steel will be 1*0.7/100 =0.007 but density of steel is 7850 kg/ cum so 0.007*7850=54.95 say 55 kg per cum so steel required to reinforce 1 cum concrete for slab is approximately 55 kgs.
The amount of steel reinforcement required for a 1 m³ slab of concrete typically ranges from 80 to 150 kg, depending on the design and load requirements. A common guideline is to use approximately 0.5% to 1% of the concrete volume as steel reinforcement. However, the exact quantity can vary based on factors such as slab thickness, structural specifications, and local building codes. It's always best to consult a structural engineer for precise calculations.
i dn k=12*45
The steel sheet in question has a volume of 1 x 1 x 0.002 m3. Mild steel has a density of 7800 kg/m3.[A]As such the mass = 7800 x 0.002Mass = 15.6 kg[A] Cobb, F. (2009) Structural Engineer's Pocket Book, 2nd Edition. Amsterdam, Elsevier.
Concrete is composed of cement and other cementitious materials such as fly ash and slag cement, coarse aggregate made of crushed stone, fine aggregate such as sand, water, and chemical admixtures. In reinforced concrete, steel is introduced in to the concrete. In plain concrete, no steel reinforcement is introduced. Generally tensile and compressive strength is taken by reinforced concrete and only compressive strength is taken by plain concrete
7600 kg
The amount of steel required for a 1-meter pile depends on the pile's design, including its diameter, shape, and reinforcement requirements. Generally, for a reinforced concrete pile, the steel reinforcement can range from 50 to 100 kg per meter, depending on the specific engineering requirements. For accurate calculations, it's essential to consult structural design specifications or a structural engineer.
Cost is dependant on the grade and form and where it is produced - labour costs.
well , reinforcement steel required for slab is nearly 0.7 to 0.8% of the volume of concrete so if concrete is 1 cum then steel will be 1*0.7/100 =0.007 but density of steel is 7850 kg/ cum so 0.007*7850=54.95 say 55 kg per cum so steel required to reinforce 1 cum concrete for slab is approximately 55 kgs.
The amount of steel reinforcement required for a 1 m³ slab of concrete typically ranges from 80 to 150 kg, depending on the design and load requirements. A common guideline is to use approximately 0.5% to 1% of the concrete volume as steel reinforcement. However, the exact quantity can vary based on factors such as slab thickness, structural specifications, and local building codes. It's always best to consult a structural engineer for precise calculations.
The steel volume in 1 m³ of concrete depends on the design and requirements of the structure. Typically, reinforced concrete might contain between 100 to 200 kg of steel reinforcement per cubic meter, which translates to approximately 0.1 to 0.2 m³ of steel, considering the density of steel is about 7850 kg/m³. However, the exact volume can vary based on factors like load requirements, structural design, and safety codes. For precise calculations, consulting engineering specifications is essential.
Both 1 kg of steel and 1 kg of cotton weigh the same amount and would require the same amount of force to lift. The difference lies in the volume and density of each material, where steel would be smaller and denser than cotton.
If 1 kg of tomatoes costs 5 CHF, 0.1 kg will cost 1/10th of 5 CHF, so the cost will be 0.5 kg.
To find the cost of 1 kg when 5 kg costs 9 p (pence), you divide the total cost by the quantity: 9 p ÷ 5 kg = 1.8 p per kg. Therefore, the cost of 1 kg is 1.8 p.
The cost would be 1.5 p.
potato
To determine the total cost of 5 kg at 9p per 1 kg, you would multiply the cost per kg by the total weight. In this case, 9p per 1 kg is equivalent to £0.09 per kg. Therefore, the cost of 5 kg at this rate would be £0.09 x 5 = £0.45.