To calculate the current in a circuit, you can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In this case, with a voltage of 120 volts and a resistance of 20 ohms, the current would be I = V/R = 120V / 20Ω = 6 amperes. Therefore, the current in the circuit is 6 A.
Ohms law is: I = V / R (current = voltage / resistance)... where if the voltage or resistance changes then the current will change. ... the current and resistance is a inversely proportional linearly relationship ...this means that if the resistance doubles then the current halfs, if the resistance halfs then the current doubles, etc...hope this helps
Divide the LEDs current into the voltage and derive a proper current limiting resistor value. 16/0.02=800 ohms. That is for a 20 ma LED.
The formula you are looking for is R = E/I
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).
To find the current in a circuit, you can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In this case, with a voltage of 120 volts and a resistance of 20 ohms, the current would be calculated as follows: I = V / R = 120V / 20Ω = 6 amps. Therefore, the current in the circuit is 6 amps.
V = i*r v = 2 * 60 v= 120v
"Volts" is electrical pressure applied to a circuit; whereas, "ohms" is electrical resistance to that pressure. One cannot determine ohms from voltage without knowing either the current (in "amps") or power (in "watts"). A normal 120V household circuit can handle a maximum of 20 amps, so using ohm's law of resistance = voltage / current, the minimum resistance required in a 120V household circuit would be 6 ohms. Any less than 6 ohms will cause the circuit breaker to trip.
I=V/R Which means: amps(current) = voltage divided by resistance. 20= V/20
Ohms law is: I = V / R (current = voltage / resistance)... where if the voltage or resistance changes then the current will change. ... the current and resistance is a inversely proportional linearly relationship ...this means that if the resistance doubles then the current halfs, if the resistance halfs then the current doubles, etc...hope this helps
Ohm's Law Volts = Current x Resistance Amps = V / R 110 / 20 = 5.5 Amps
The answer is 20 divided by 40, in amps.
20V / 5ohms = 4A
If a lightbulb has a resistance of 250 ohms, the voltage required for the bulb to draw a current of 0.5 A is 125 V. (Ohm's law: voltage equals current times resistance)Unfortunately, its more complicated than that...Is the resistance of 250 ohms the hot resistance or the cold resistance? It matters. It matters very much.Light bulbs have a dramatic positive resistance to temperature coefficient. It is not uncommon for the instantaneous on power to be 10 or 20 times the nominal value.So, if the 250 ohms is the measured resistance while operating at a current of 0.5 A, then 125 V is the correct answer. If the resistance is the cold resistance, you need to go back and find out the hot resistance at the desired operating point.
Divide the LEDs current into the voltage and derive a proper current limiting resistor value. 16/0.02=800 ohms. That is for a 20 ma LED.
The formula you are looking for is R = E/I
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere