Ohms law is: I = V / R (current = voltage / resistance)... where if the voltage or resistance changes then the current will change. ... the current and resistance is a inversely proportional linearly relationship ...this means that if the resistance doubles then the current halfs, if the resistance halfs then the current doubles, etc...hope this helps
The formula you are looking for is R = E/I
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
Divide the LEDs current into the voltage and derive a proper current limiting resistor value. 16/0.02=800 ohms. That is for a 20 ma LED.
The voltage is gained by multiplying the current and resistance together, i.e.. 50 x 500 = 25000 Imagine the three as a triangle with the voltage at the top, and the current and resistance at the bottom- V . ---- . I x R The voltage divided by the current is the resistance and the voltage divided by the resistance is the current. Therefore the current times the resistance is equal to the voltage. Having any two of these figures allows you to find the third.
To find the current in a circuit, you can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In this case, with a voltage of 120 volts and a resistance of 20 ohms, the current would be calculated as follows: I = V / R = 120V / 20Ω = 6 amps. Therefore, the current in the circuit is 6 amps.
V = i*r v = 2 * 60 v= 120v
"Volts" is electrical pressure applied to a circuit; whereas, "ohms" is electrical resistance to that pressure. One cannot determine ohms from voltage without knowing either the current (in "amps") or power (in "watts"). A normal 120V household circuit can handle a maximum of 20 amps, so using ohm's law of resistance = voltage / current, the minimum resistance required in a 120V household circuit would be 6 ohms. Any less than 6 ohms will cause the circuit breaker to trip.
I=V/R Which means: amps(current) = voltage divided by resistance. 20= V/20
Ohms law is: I = V / R (current = voltage / resistance)... where if the voltage or resistance changes then the current will change. ... the current and resistance is a inversely proportional linearly relationship ...this means that if the resistance doubles then the current halfs, if the resistance halfs then the current doubles, etc...hope this helps
Ohm's Law Volts = Current x Resistance Amps = V / R 110 / 20 = 5.5 Amps
The answer is 20 divided by 40, in amps.
20V / 5ohms = 4A
If a lightbulb has a resistance of 250 ohms, the voltage required for the bulb to draw a current of 0.5 A is 125 V. (Ohm's law: voltage equals current times resistance)Unfortunately, its more complicated than that...Is the resistance of 250 ohms the hot resistance or the cold resistance? It matters. It matters very much.Light bulbs have a dramatic positive resistance to temperature coefficient. It is not uncommon for the instantaneous on power to be 10 or 20 times the nominal value.So, if the 250 ohms is the measured resistance while operating at a current of 0.5 A, then 125 V is the correct answer. If the resistance is the cold resistance, you need to go back and find out the hot resistance at the desired operating point.
The formula you are looking for is R = E/I
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
Divide the LEDs current into the voltage and derive a proper current limiting resistor value. 16/0.02=800 ohms. That is for a 20 ma LED.