Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
Just use Ohms Law: V=IR, that is, voltage (in Volt) = current (in Ampere) x resistance (in Ohms).
Current, I is equal to V (voltage) divided by R (resistance); Hence: I=V/R = 9V/200 ohms: I = 0.045 Amps, or 45ma (milliamps).
75 ohms. R = E/I.
Just use Ohm's Law Voltage = Current x Resistance Amps = Voltage Divided By Resistance Amps = 120 / 260
5 ohms in parallel with 20 ohms is 4 ohms. 4 ohms across 200 volts is 50 amperes. However, resistance is a function of temperature, so the 4 ohms will probably be higher, reducing the current. How much depends on the temperature coefficient of the loads.
Just use Ohms Law: V=IR, that is, voltage (in Volt) = current (in Ampere) x resistance (in Ohms).
resistance = volt / current . 440 volt across a parallel circuit means the same 440 volt across both resistance s. hence resistance r = volt / current . 440 / 20 amp = 27.5 ohms total resistance
4.8 ohms
The ohm is the unit of electrical resistance to current flow. More ohms (more resistance), the less current will flow. Less ohms (less resistance), the more current will flow. One ohm is defined as the amount of resistance that will cause one ampere of current to flow if the supply voltage is one volt. Ohm's law states that amps = volts / ohms So, if you had a 12 volt battery, and you connected a load, say a heating element that had a resistance of 3 ohms, how much current would flow in the circuit? amps = 12 volts / 3 ohms amps = 4
The current flowing through the circuit can be calculated using Ohm's Law: I = V/R, where I is the current, V is the voltage (12 volts), and R is the resistance (25 ohms). Plugging in the values, the current would be 0.48 amperes.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.
Current, I is equal to V (voltage) divided by R (resistance); Hence: I=V/R = 9V/200 ohms: I = 0.045 Amps, or 45ma (milliamps).
75 ohms. R = E/I.
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the bulb is the only component there, then the current is E/R = 9/12 = 0.75 amperes.
480 volts and 60ohm impedence current = volt/impedence current=480/60 current=8ampeares
Current = voltage/resistance If those are the only components in the circuit, then Current = 9/12 = 0.75 Ampere = 750 mA