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How much current and circuit that includes a 9- volt battery and a bulb with a resistance of 3 ohms?
A resistance of 3 ohms connected between the terminals of a 9-volt battery
will result in a current of 3 Amperes. If the battery is one of those little ones
with snaps on top, it may be able to produce 3 amperes of current for about
3 seconds before it rolls over and totally dies.
What else can I help you with?
What is the net resistance of the circuit connected to the battery in Figure 1?
The net resistance of the circuit connected to the battery in Figure 1 is the total resistance that the current encounters when flowing through the circuit. It is calculated by adding up the individual resistances of all the components in the circuit.
How much current is in a circuit that includes a 9-volt battery and a bulb with a resistance of 12 ohms?
Current = voltage/resistance If those are the only components in the circuit, then Current = 9/12 = 0.75 Ampere = 750 mA
How is a circuit constructed with five resistors and a battery as shown?
A circuit with five resistors and a battery is constructed by connecting the resistors in series or parallel to create a closed loop for the flow of electric current from the battery through the resistors. The battery provides the energy for the current to flow through the resistors, which resist the flow of current. The arrangement of the resistors and the battery determines the overall resistance and current flow in the circuit.
What is meant by calculate the equivalent resistance of the circuit from the measured potential difference across the battery and the current through the battery is there a formula for this?
In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.
What is lost volts?
A battery is rated to supply a certain number of volts. However, it actually supplies less, because they are "lost" as the current has to get out of the battery in the first place.(The battery has internal resistance)The amount of lost volts depends on the current being drawn:The less resistance a circuit has, the more current is drawn, because it's easier to flow.Example:If the circuit has little resistance, it draws a large current and the battery's internal resistance causes more lost volts.If the circuit has high resistance, it draws a small current and there are fewer lost volts.This is why when you short-circuit a battery (give it hardly any resistance to go through) it heats up and may explode. A large current is drawn and all the volts are used by the battery's internal resistance.
If you have a circuit consisting of a battery and a wire What two factors determine the amount of current in the circuit?
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
What would the current flow be if a short circuit is put across the battery's terminals?
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.
Is a car battery a circuit?
Hi, there. A battery is a power supply, a source of potential difference which drives current. In itself, a battery is not a circuit, but if you attach it to a load (a resistance), then a current will form and a circuit is made!
When the wires are connected to the terminals of the battery what causes electric current in a circuit?
The resistance of the load is what causes an electric current to flow in a circuit.
What is the net resistance of the circuit connected to the battery in Figure 1?
The net resistance of the circuit connected to the battery in Figure 1 is the total resistance that the current encounters when flowing through the circuit. It is calculated by adding up the individual resistances of all the components in the circuit.
How much current is in a circuit that includes a 9-volt battery and a bulb with a resistance of 12 ohms?
Current = voltage/resistance If those are the only components in the circuit, then Current = 9/12 = 0.75 Ampere = 750 mA
If a series circuit has a 12 v battery what is the current flow?
You'd need to know either the resistance or the wattage of the circuit. Ohm's Law: Current = Voltage divided by resistance or Current = Power divided by Voltage
If a parallel circuit shorts at the battery will the entire circuit short out too?
If at battery,parallel circuit shorts then equivalent resistance of circuit becomes approximately 0 Ohms,and therefore as current follows low resistance path infinite amount of current due to low resistance will flow through the wire so,entire parallel circuit will short out,but wire will burn and battery may get damaged. Name:Sumit Karnik.
How is a circuit constructed with five resistors and a battery as shown?
A circuit with five resistors and a battery is constructed by connecting the resistors in series or parallel to create a closed loop for the flow of electric current from the battery through the resistors. The battery provides the energy for the current to flow through the resistors, which resist the flow of current. The arrangement of the resistors and the battery determines the overall resistance and current flow in the circuit.
What is the relationship among voltage circuit and resistance in a circuit?
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
How much available current in a 9 volt battery?
It depends on the resistance of the circuit, as V=IR, so I=V/R (V=Voltage, I=Current, R=Resistance)
What is meant by calculate the equivalent resistance of the circuit from the measured potential difference across the battery and the current through the battery is there a formula for this?
In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.
