A transformer requires a 75-kVA minimum load in order to be set.
HID lights is where I have seen that application although I do not understand why it is put there, instead of parallel with the load.
A: The only way can be possible if the transformer is an isolation type. Yes, you can put the input into the secondary side. This will create a step-up transformer.
A transformer can change any AC voltage to any other AC voltage. But if you put DC into a transformer, the main component at the output is smoke. Furthermore, sir, you have insulted 12 volts by implying that it is undesirable.
It's common to put arcing horns on the HV side of a power transformer to short out voltage spikes arriving from lightning strikes along the line.
On a 1kva you have 1000 watts capacity. To fine the current the formula is I = W/E. The secondary side of the transformer has the capacity of 1000/120 = 8.3 amps. In your question you do not put the amps across the secondary you draw amps from it. Using the transformer to its maximum, without overloading it, the primary will be 4.16 amps at 240 volts and the secondary will be 8.33 at 120 volts. <<>> voltage times amps equals wattage
It could be a couple of things. Voltage drop is one, if the distance of the load is too far from the source of power this will happen. The other thing is if you are using a step down transformer and it is under sized, as soon as you apply the load the transformer output will drop off. If this condition lasts the transformer will eventual fail.
Transformers voltage ratings are typically at full load. For instance, A 24 VAC, 10A transformer will have a terminal voltage of 24 when it is feeding 10 amps to a load. Since the transformer windings have some resistance, the transformer designer has to wind the transformer to put out more than 24 volts, since some of the voltage will be lost, dropped across the resistance of the secondary windings. But, according to Ohm's law, the voltage dropped across a resistance is proportional to the current (E=IR). If we take away the 10A load, there is no current, and therefore no winding voltage drop! The excess voltage the designer built in now appears at the terminals. This is the no-load voltage. In my example above, when we remove the 10A load, the output voltage of the transformer might rise to 26.4V. We would say the no-load voltage of that transformer is 26.4V The ratio of full-load voltage to no-load voltage is called the transformer's "regulation factor". It is calculated as: (no-load voltage - full-load voltage) / full-load voltage * 100. Ours is: ((26.4 - 24) / 24) * 100 = 10%.
Losses due to loading. As more load (more current) is put on a transformer, these losses will increase. They are often referred to as I2R (or I^2*R) losses.
I'm assuming these are RMS values. Power is equivalent to the voltage times the current: 30VA = 24*I I = 1.25A. If the load is 30VA, you should put in a fuse larger than 1.25A. If the transformer this is coming from is rated at 30VA, and the load is below this (say typically 20 watts resistive load), you may want to undersize the fuse to insure the transformer is protected.
The purpose of a transformer is to transform one voltage to another voltage. This can be in the configuration of stepping up the voltage or stepping down the voltage . The load is what establishes what the current from the transformer is going to be.
The transformer enclosure should isolate the transformer sufficiently from the environment. I believe OSHA specifies 2 feet, 1 inch as the minimum appoach distance to 13.8kV, so I suppose a transformer could be put this close to a building and still be safe. My guess is there are codes in place in your local area that prevent this and specify some greater distance.
You can if done carefully. The neutral of one transformer must be set up to be at the positive voltage of the other transformer. This might require an intermediate step transformer that is center tapped (so three instead of 2 transformers).
HID lights is where I have seen that application although I do not understand why it is put there, instead of parallel with the load.
Yes, but it's going to require an oversize load permit.
A transformer is used to transfer electricity from one circuit to another.
A: The only way can be possible if the transformer is an isolation type. Yes, you can put the input into the secondary side. This will create a step-up transformer.
Well, honey, it's simple physics. Even when there's no load, there's still friction and other forces at play that require effort to overcome. So, whether you're lifting a feather or a boulder, you're still gonna have to put in some work to get that zero load moving. It's just the way the cookie crumbles, darling.