The formula for power is W = v2/R therefore the resistance is v2/W where v2 = v*v or v-squared.
due to a font fault these formulas cannot be expressed correctly. But the answer to the question is R = 240*240/75 ohms.
When it is bright, a Light Dependent Resistor (LDR) has low resistance. LDRs are designed to decrease their resistance in response to increased light levels, allowing more current to flow through them. Conversely, in low light conditions, their resistance increases. Thus, the resistance of an LDR is inversely proportional to the intensity of light it receives.
Yes, the resistance of the filament of a light bulb is what generates enough heat to make the filament glow and produce light.
The resistor whose resistance decreases when light falls on it is called a photoconductor or photoresistor. A common type of photoresistor is made of cadmium sulfide (CdS) and is often used in light-sensitive applications. These devices exhibit a decrease in resistance as the intensity of light increases, allowing them to function as light sensors.
The electrical resistance of a light bulb increases when it is turned on As a resistor, the tungsten light bulb has a positive resistance coefficient. This means that the electrical resistance goes up when the filament becomes hot. For example, a 100 watt light bulb operated at 120 volts - it does not matter if it is AC or DC for this calculation - will have a resistance of 144 ohms when hot and draw .833 ampere. When cold the filament typically has a resistance of only 10 ohms which increases as the filament heats up.
A light-dependent resistor (LDR) produces a variable resistance output based on the intensity of light it is exposed to. In low light conditions, the resistance of the LDR is high, resulting in a lower current flow, while in bright light, the resistance decreases, allowing more current to flow. This change in resistance can be used to generate an analog voltage signal when connected to a circuit, making it useful for light-sensing applications.
Yes. The resistance of a globe depends not only on the wattage of it but also on the voltage. A 12 V Globe would has a quarter the resistance of a 24 volt globe for the same wattage. (when alight)
To calculate current passing through a light globe, you can use Ohm's Law: current (I) = voltage (V) / resistance (R). To calculate voltage across a light globe, you can rearrange Ohm's Law to solve for voltage: voltage (V) = current (I) * resistance (R). Just make sure you know the resistance of the light globe in ohms.
Globe. Light globe or light bulb Globe of the World
Tungsten is the main transition metal used in drill bits and light globe filaments due to its high melting point, hardness, and resistance to heat and wear.
the globe light will be on
P=VI => I=P/V => I=60W/12V => I=5A 5 amps when the globe is operating
connectivity between host and switch can be examined by light of switch ports.
The frosted globe gave the light a soft glow.I showed the boy where he was on the globe of the world.
I think Albert Einstein invented the light globe
To replace a ceiling light globe, first turn off the power to the light fixture. Then, carefully remove the old globe by unscrewing it or twisting it off. Next, insert the new globe by screwing or twisting it into place. Finally, turn the power back on and test the light to ensure it is working properly.
no
The best time to schedule a light globe replacement in your home is when the current light globe burns out or stops working. It is important to replace it promptly to ensure proper lighting and safety in your home.