Rs . 12
A gen set will be rated for a certain kVA at a certain power factor, or certain kW at a certain power factor. If rated in kVA, the power factor indicates the amount of real power you will get (ie if rated at 10,000kVA at .95 pf, the gen set can generate .95 x 10,000kW, or 9,500kW).
one
A transformer requires a 75-kVA minimum load in order to be set.
Vicelords stacj by throwing up numerous signs represnting their set.
what should be height of stack of 1250 kva D.G as per Indian pollution boardA: it should be 7.1 meter + building height of 1250kva Dg set installed.
What is the minimum height required for chimney of 100 KVA DG Set which is kept in
Rating for DG set and any of electrical machines is calculated in KVA. KVA is calculated as KW/pf. One can calculate the required KVA for DG set with this formulation: (KW/pf)/load rate. For example KW=110, pf=0.8 and one loads the DG at 75%, so KVA= (110/0.8)/0.75=185 KVA.
They are members of the infinite set of numbers of the form 1250*k where k is an integer. Since the set is infinite, it is not possible to list them. 1250, 2500, 3750 and so on.
To find the number that, when multiplied by 3, equals 1250, you can set up the equation as follows: 3x = 1250. To solve for x, divide both sides by 3: x = 1250 / 3. Therefore, the number that, when multiplied by 3, equals 1250 is approximately 416.66.
The stack is a region of memory set aside to store register values and operands.
i try ......gen set 120 KVA and output 415 Volt 1 KVA = 0.8KW so 120 x 0.8 = 96 kW A = w/v ~ A = 96000/415 = 231.3 Amp I' it right ? If wrong give correction
Rs . 12
A gen set will be rated for a certain kVA at a certain power factor, or certain kW at a certain power factor. If rated in kVA, the power factor indicates the amount of real power you will get (ie if rated at 10,000kVA at .95 pf, the gen set can generate .95 x 10,000kW, or 9,500kW).
one
voltage=400 volts current=17.1 ampere assumed total load since IL=KVA X 1000x0.8/400 therefore kva=17.1x400/1000x08 =8.55kva Gen set
To find the value that, when multiplied by 500, equals 1250, you can set up the equation 500x = 1250. To solve for x, you would divide both sides by 500, giving you x = 1250 / 500. Simplifying this further, you get x = 2. Therefore, 2 times 500 equals 1250.