This depends on the actual battery and what it is made of.
A 1.2 volt rechargable NiMh battery typically gives off a voltage of 1.3 to start with, then it rapidly goes down to 1.2 volt where it stays stable until almost empty, then it quickly drops below and down to .5 volt or even further down..
The same applies to Lead Acid or NickelCadmium batteries.
Different types of batteries have different properties.
NickelCadmium normally are able to give a lot of current until empty.
where as the current you get from a NiMh battery is rather limited.
Lead Acid are capable of a very high current but still dependant on the internal design of the battery.
Unfortunately one can not give a correct (for all) answer to a general question.
Regards.
Regardless of the microfarad value of a cap(s), the total voltage of the circuit will equal the available voltage available. I.e. 10V applied to several (or one) cap'(s) will eventually reach the available voltage (Source). This is due to the fact that a cap is not resistive, or inductive.
I think you mean 35Ah (Ampere-hours) This depends on the amount of energy that can be stored. The amount of energy in car batteries is usually expressed in Ah, and depends on the voltage of the battery. In Europe, mostly 12V, 40Ah to 70Ah. Let's say a battery of 35Ah 12V (in reality, a fully charged lead-acid battery will have 12,65V over its open poles) needs to be fully charged. 35Ah means tha it can, theoretically, deliver 35A at 12V during 1 hour. That's is a total power storage of 12x35 = 420Wh = 1512kJ (kiloJoules) The amount of current flowing into the battery will charge (by an electrochemical process) the battery. So it's not really the voltage of the battery, but the current that's important. Unless you know the internal resistance of the battery, You can not really calculate this. But now practical. You can charge a car battery at a pretty high current, although quality deteriorates with higher currents (that's why professional chargers will use a pulse charger) , so your 13,5V will not be too high. Car generators can deliver up to 16Volts to a battery. What I suggest is this: measure the battery voltage, load the battery with the 13,5V, and measure again after 10 minutes. Check the voltage of the battery, and do not exceed 12,5V. Even better: Load the battery, and meanwhile measure the current and voltage. Now you can calculate the internal resistance of the battery. A word of caution. Car batteries contain a highly poisonous fluid, a mix of water an sulfuric acid. Don't play around with it, DON'T SHORT IT, don't reverse polarisation, This fluid causes severe burns. Be careful.
Total voltage output of 5 2v cells connected in series would be 10v
When a 1.5V battery and a 3V battery are connected in series across a bulb, the total voltage supplied is 4.5V. This voltage exceeds the rated voltage of the bulb, causing it to draw too much current. As a result, the bulb may flash brightly initially but then burn out or go out due to overheating or damage from the excessive voltage.
total voltage = 4.5V, total resistance = 3.5 ohms, loop current = 4.5V / 3.5 ohms = 1.286Atotal voltage = 9V, total resistance = 4 ohms, loop current = 9V / 4 ohms = 2.25Atotal voltage = 13.5V, total resistance = 4.5 ohms, loop current = 13.5V / 4.5 ohms = 3Aetc.There is no solution to your problem conditions.
ask the battery. Not me
Midpoint voltage in a battery bank refers to the voltage level at the midpoint of a series of connected batteries, which can indicate the overall state of charge and health of the battery system. It is typically measured between the positive terminal of the first battery and the negative terminal of the last battery in the series. In a balanced battery bank, the midpoint voltage should be approximately half of the total voltage of the series, assuming all batteries are equally charged and healthy. Monitoring midpoint voltage helps to identify issues such as imbalanced cells or potential failures within the battery bank.
When batteries are connected in parallel, the total voltage remains the same as the voltage of a single battery.
Yes.If you connect the batteries in series the total voltage will be the sum of the voltages of the batteries.For example if you connect a 12 volt battery in series with a 6 volt battery the total voltage will be 18 volts.
When connecting batteries in parallel, the total voltage output remains the same as the voltage of a single battery.
Regardless of the microfarad value of a cap(s), the total voltage of the circuit will equal the available voltage available. I.e. 10V applied to several (or one) cap'(s) will eventually reach the available voltage (Source). This is due to the fact that a cap is not resistive, or inductive.
When a battery is added to a parallel circuit, the total voltage in the circuit increases as the new battery adds its voltage to the existing voltage sources. The total current in the circuit may also increase as the additional voltage motivates the charges to flow through the parallel branches of the circuit.
The amount of voltage produced in a battery is determined by the types of chemical reactions occurring within the battery and the materials used for the electrodes. The voltage is also affected by the number of cells in the battery, with multiple cells in series increasing the total voltage output.
(A) The bias battery voltage (B) 0V (C) the diode barrier potentiaol (D) The total circuit voltage
You get the lowest voltage. Although it's not quite that simple. The higher voltage batteries will charge up the lower voltage ones to some extent, so you'll get the highest voltage that the lowest voltage battery can support while being charged by the other batteries.
To increase the total voltage output, connect the 3 batteries in series by connecting the positive terminal of one battery to the negative terminal of the next battery, and so on. This will result in a total output voltage of 4.5 volts.
7.5 Volts