No, the use of 'namespace std' is not compulsory. You can specifiy it on any object reference. Specifying 'namespace' simply provides a default value.
Contrast ...
using namespace std;
cout << "Hello world!" << endl;
... with ...
std::cout << "Hello world!" << std::endl;
No. You can't use namespace std even if you include stdio.h. At the very least you must include stddef.h before you can use namespace std.
#include <iostream> using namespace std;
A namespace is similar to a class in object oriented programming. A namespace contains functions defined by the programmer. for example namespace std contains functions like cout and cin.namespaces can be globaly declared like so: "using namespace std;"which includes all the functions located in the namespace std.if you only need to use cout you can globaly declare only cout like this "using std::cout;"orstd::cout
The std namespace is the standard library, which includes many of the common data types, constants, structures, classes and functions that you will use to create C++ programs. There are very few non-trivial C++ programs that do no make use of at least some portion of the standard library at some point. Note that you need only include those portions you actually use; there is no need to include the entire standard library. Any built-in functions that require the standard library will include only as much as they need to, whether you yourself include those portions or not.
#include <iostream> using namespace std; int main() { for(int i = 0; i <= 100; i++) { if(i % 2 != 0) { cout << i << endl; } } char wait; cin >> wait; return 0; }
No. You can't use namespace std even if you include stdio.h. At the very least you must include stddef.h before you can use namespace std.
#include <iostream> using namespace std;
A namespace is similar to a class in object oriented programming. A namespace contains functions defined by the programmer. for example namespace std contains functions like cout and cin.namespaces can be globaly declared like so: "using namespace std;"which includes all the functions located in the namespace std.if you only need to use cout you can globaly declare only cout like this "using std::cout;"orstd::cout
A quick and simple way to do this would be to add 'std::' directly in front of the data type that requires it. For example: a vector data type, without the line of code 'using namespace std' would look like this: 'std::vector' (without the inverted commas).
greatest = std::max (a, std::max(b, c));
#include<iostream> int main() { using namespace std; cout<<"Hello world!"<<endl; return( 0 ); }
#include<iostream> int main() { using namespace std; cout<<"Hello world!"<<endl; return(0); }
Use setprecision.Example:#include #include using namespace std; int main() { double f = 3.14159; cout
If you do not include the directive using namespace stdin your program, any references to objects in namespace std will need be be qualified with that namespace. For instance...cout
Download Dev-C++. Just google it. Hello World: #include <iostream> using namespace std; int main() { cout << "Hello World" << endl; }
#include <iostream> using standard namespace std; int main() { cout << "your prob shouldn't be taking c++"; return 0; }
#include<iostream> int main() { using namespace std; char c='A'; do { cout<<c; }while(c++<'Z'); cout<<endl; }