I assume that you are speaking theoretically, as it is unlikely that a practical transformer will have just ten turns ('loops') in its secondary coil. In any event, you have not provided sufficient information to be able to answer your question, as it's necessary to know how many turns there are on the primary winding.
Transformers are rated in KVA, both the primary and secondary windings have the same KVA rating. (KVA is the voltage multiplied by the amperage then divided by 1000). If you have a 10 KVA step up transformer with 120V on the primary: A = 10k / 120 = 83.33A and if the secondary produces 240V: A = 10k / 240 = 41.667A
The transformer primary winding is connected to the alternating current supply. This causes a varying current in the primary winding, which creates a varying magnetic field in the transformer core. Because the primary voltage is alternating, the flux is also alternating - expanding and contracting, and changing polarity in time with the supply. This alternating core flux 'cuts' the secondary winding/s of the transformer, and induces a voltage in the secondary coil/s. As long as there is a magnetic field that is moving, and a conductor for it to move across, it will induce a voltage in the conductor. While the actual induced voltage depends on the amount of flux, the amount of conductor material and the rate of change of the flux, the actual voltage can be calculated from: Vsec = ((Vprim * Nsec) / Nprim) where V = voltage, N = number of turns of wire in the coil, prim = primary and sec = secondary. Transformers don't work on DC - they give a brief pulse out at switch-on and switch-off, because that's the only times the current is changing and the flux is moving. If you have to transform DC, you use a switching circuit that 'chops' the DC into a series of pulses that simulate AC as far as the 'moving flux' requirements of the transformer are concerned.
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
A Buck Boost transformer is an auto transformer with a small primary to secondary voltage difference. It effectively adds or subtracts a few windings to the secondary to increase or decrease voltage. Here is an example: Say I have a 110 v and want 120 v; I have an auto transformer with 120 windings, tapped at 110 and 120. If I connect the 110 connection to my incoming 110v line, the voltage at the 120 tap will be 120v.
Transformers have windings - typically each winding is designated for a particular voltage. Any one of the windings can be an "output", as any winding can be an "input". Usually for consumers, one of the windings is intended to be 120V for the input. In that case, all of the other windings would be an output.I should also mention that while you can have several outputs, you can only have one input. Some transformers have the windings color coded to designate input and outputs.Hope this helps!
As far as a transformer is concerned, the secondary voltage Vs value cannot be determined by the primary voltage Vp alone. For the simplest of calculations the transformer primary-secondary turn ratio must be known. For an ideal transformer ( and practicaly ideal transformers don't exist as there will be various losses in the transformer cores and windings), the simple equation relating secondary voltage to primary voltage would be : Vs/Vp=Ns/Np=Ip/Is where Ns is the number of winding turns in the secondary of the transformer, and Np the primary. Ip is the primary current and Is the secondary.
Well transformers are used to either raise the voltage (step-up) or lower the voltage (step-down). Transformers have a high voltage winding (HV) and Low voltage winding (LV). If being used as step down then the supply will be connected to the winding with more turns and load will be connected to winding with fewer turns. This is reffered to as the turns ratio N1/N2 .If the ratio is 1/1 and 120V applied then the secondary voltage is 120v. If N1/N2 is 2/1 then there are twice and many primary turns as secondary turns and if 120 V applied to primary there would be 60 V on secondary.
to maintain the same secondary voltage output from the transformer the primary transformer is wound for operation but it is split exactly in the centre.when used as an ac the two half of the primary are connected in series producing the designed output from the secondary.example if used on a 120v line the 2 halves of primary are connected in parallel producing 25v from the secondary and paver(vA) at of the transformer is the same
to maintain the same secondary voltage output from the transformer the primary transformer is wound for operation but it is split exactly in the centre.when used as an ac the two half of the primary are connected in series producing the designed output from the secondary.example if used on a 120v line the 2 halves of primary are connected in parallel producing 25v from the secondary and paver(vA) at of the transformer is the same
Transformers are rated in KVA, both the primary and secondary windings have the same KVA rating. (KVA is the voltage multiplied by the amperage then divided by 1000). If you have a 10 KVA step up transformer with 120V on the primary: A = 10k / 120 = 83.33A and if the secondary produces 240V: A = 10k / 240 = 41.667A
Assuming the transformer is ideal, the current on the primary side can be calculated using the formula for power: P(primary) = P(secondary). Since power is the product of voltage and current, the current on the primary side would be 1.38 amps (277V x Iprimary = 120V x 6A).
120V stands for 120 volts, which is the standard voltage used in most residential electrical systems in the United States. This voltage is supplied by the electrical utility to power household appliances, lighting, and electronics. When a device is plugged into a 120V outlet, the voltage provides the necessary electrical energy for the device to function properly.
The transformer primary winding is connected to the alternating current supply. This causes a varying current in the primary winding, which creates a varying magnetic field in the transformer core. Because the primary voltage is alternating, the flux is also alternating - expanding and contracting, and changing polarity in time with the supply. This alternating core flux 'cuts' the secondary winding/s of the transformer, and induces a voltage in the secondary coil/s. As long as there is a magnetic field that is moving, and a conductor for it to move across, it will induce a voltage in the conductor. While the actual induced voltage depends on the amount of flux, the amount of conductor material and the rate of change of the flux, the actual voltage can be calculated from: Vsec = ((Vprim * Nsec) / Nprim) where V = voltage, N = number of turns of wire in the coil, prim = primary and sec = secondary. Transformers don't work on DC - they give a brief pulse out at switch-on and switch-off, because that's the only times the current is changing and the flux is moving. If you have to transform DC, you use a switching circuit that 'chops' the DC into a series of pulses that simulate AC as far as the 'moving flux' requirements of the transformer are concerned.
No. The neon sign is fed by a step-up transformer. Primary side 120V, secondary side 7500V. If you applied 240 to the primary side you would get 15000 volts on the neon tube. A flash over and then nothing. If you can find a transformer from 120V to 240V or 240V to 120V then you are good to go. Connect 240V to 240V side and you will get 120V out the other, connect the 120V side to the neon sign and you should have light. Transformer should be at least 100va. This will give you an output of .83 amps at 120V
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
To convert voltage from primary coil to secondary coil in a transformer, you can use the formula VP/VS = NP/NS, where VP is primary voltage, VS is secondary voltage, NP is number of turns in primary coil, and NS is number of turns in secondary coil. Given VP = 120V, VS = 24V, and we need to show the primary coil has 5 times as many turns as the secondary coil. Plug in the values: 120/24 = NP/NS. Solving for the ratio of turns, we get NP/NS = 5. This means the primary coil has 5 times as many turns as the secondary coil in this transformer scenario.
A Buck Boost transformer is an auto transformer with a small primary to secondary voltage difference. It effectively adds or subtracts a few windings to the secondary to increase or decrease voltage. Here is an example: Say I have a 110 v and want 120 v; I have an auto transformer with 120 windings, tapped at 110 and 120. If I connect the 110 connection to my incoming 110v line, the voltage at the 120 tap will be 120v.