Assuming the transformer is ideal, the current on the primary side can be calculated using the formula for power: P(primary) = P(secondary). Since power is the product of voltage and current, the current on the primary side would be 1.38 amps (277V x Iprimary = 120V x 6A).
Is 120 V the primary or secondary voltage? If the primary (input) voltage is 120, then at full load the transformer will draw about 0.42 A from the line, and the current delivered to the load depends on the secondary (output) voltage. If the secondary (output) voltage is 120, then at full load the transformer will deliver about 0.42 A to the load, and the current drawn fom the line depends on the primary (input) voltage. amps = watts / volts So, for instance, if your transformer has a 120 V primary, and a 24 V secondary, as you might find in your AC unit or furnace: Primary current (at full load) - A = W / V A = 50 / 120 A = 0.4166 Secondary current - A = 50 / 24 A = 2.08
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.
The amp draw of a MR16 light with a transformer can vary depending on the wattage of the light bulb and the efficiency of the transformer. Typically, a 50 watt MR16 halogen bulb with a transformer can draw around 0.42 amps. It is important to check the specifications of your specific MR16 light and transformer to determine the exact amp draw.
To calculate the amperage drawn by a 240V 12VA transformer, use the formula: Amperage = Power (VA) / Voltage (V). In this case, it would be 12VA / 240V = 0.05A. Therefore, the transformer would draw 0.05 amps.
To calculate the amperage, you can use the formula: Amps = (kW × 1000) / (√3 × Volts). Plugging in the values, we get: Amps = (45 × 1000) / (√3 × 208) ≈ 131.1 amps. So, the hot water heater would draw approximately 131.1 amps.
The primary current of a transformer depends upon the secondary current which, in turn, depends upon the load supplied by the transformer. There is not enough information in the question to determine the rated primary and secondary currents of the transformer.
On a 1kva you have 1000 watts capacity. To fine the current the formula is I = W/E. The secondary side of the transformer has the capacity of 1000/120 = 8.3 amps. In your question you do not put the amps across the secondary you draw amps from it. Using the transformer to its maximum, without overloading it, the primary will be 4.16 amps at 240 volts and the secondary will be 8.33 at 120 volts. <<>> voltage times amps equals wattage
-Yes, the transformer draw current when secondary open. Because, the secondary of the transformer is open, the primary draws only no-load current, which will have some copper loss. Therefore, power is no longer transferred from primary to secondary in this approximation, and negligible current goes through the secondary windings.Some current will flow through the primary as well as secondary to magnetise the core to maintain the internet relaship between primary &secondary winding as the winding consist of small resistance it is neglected practically hence the current will at at no load also which is small in magnitude compared to the full load current.Thta is why we says that transformer draws current when secondary is open.
A: If the transformer is connected to a power input of course it will draw current. The primary is a long wire it has own resistance wrap around an iron core. Of course there will be primary current whether there is a load on the secondary or not.
Is 120 V the primary or secondary voltage? If the primary (input) voltage is 120, then at full load the transformer will draw about 0.42 A from the line, and the current delivered to the load depends on the secondary (output) voltage. If the secondary (output) voltage is 120, then at full load the transformer will deliver about 0.42 A to the load, and the current drawn fom the line depends on the primary (input) voltage. amps = watts / volts So, for instance, if your transformer has a 120 V primary, and a 24 V secondary, as you might find in your AC unit or furnace: Primary current (at full load) - A = W / V A = 50 / 120 A = 0.4166 Secondary current - A = 50 / 24 A = 2.08
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.
Since this transformer has a ratio of 1:2 the load current on the 480V side just has to be doubled. 85 x 2 = 170A on the primary. 40.8 KVA transformer. To prove this just find the KVA of both sides and they should be equal.
The amp draw of a MR16 light with a transformer can vary depending on the wattage of the light bulb and the efficiency of the transformer. Typically, a 50 watt MR16 halogen bulb with a transformer can draw around 0.42 amps. It is important to check the specifications of your specific MR16 light and transformer to determine the exact amp draw.
The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
To calculate the amperage drawn by a 240V 12VA transformer, use the formula: Amperage = Power (VA) / Voltage (V). In this case, it would be 12VA / 240V = 0.05A. Therefore, the transformer would draw 0.05 amps.
Usually for this type of installation there is a control transformer installed in the starter enclosure. The primary of the transformer is the motors line voltage and the secondary is the control voltage which is usually 120 volts. In Canada the control transformer needs fusing on the secondary side of the transformer. In the US the transformer needs fusing on the primary and secondary sides of the transformer. The secondary side of the transformer's terminals are labeled X1 and X2. The X2 lead is grounded to the starter's enclosure. From this point out the wire is then termed the circuit's neutral wire. This wire then connects to one side of the magnetic starters draw in coil. Yes, 120 volt coil would require a neutral, this could be derived from the control transformer if it has one or from an external source.
A magnetic field is produced when there is a current in the primary coil of a transformer.^^^^basically magnectic fieldA changing current in the primary-winding of a transformer produces a changing magnetic flux in the core which results in a back-emf. in the primary winding through self induction, and a voltage in the secondary winding due to mutual induction.