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What is the voltage of a battery that supplies a current of 42 A across 3 resistors who each have a resistance of 4 ohms?
There is insufficient information in the question to properly answer it.
You need to specify if the resistors were in series or parallel.
Also, it is incorrect to say "current ... across" - it must be "current ... through".
Assuming that you mean a series circuit then it can be solved:
R(total) = Sum of the resistors in series
R(tot) = 3 x 4 Ohm
= 12 Ohm
Ohm's Law:
V = IR
V = 42 x 12
= 504 Volts
(Note: Because Ohm, Volt and Ampere were named after scientists they are always given capital letters. Ohm not ohm)
What else can I help you with?
How is a simple ohmmeter constructed?
A simple ohmmeter is constructed using a battery, a galvanometer, and a set of resistors. The battery supplies a constant voltage, while the galvanometer measures the current flowing through the circuit when a resistor is connected. The resistance is calculated using Ohm's Law (R = V/I), where V is the battery voltage and I is the current indicated by the galvanometer. The device may also include a scale or a dial to provide a direct reading of resistance values.
What is true about series connections of resistors?
The more resistance there is, the harder it is for current to flow. So the total resistance is the sum of all resistors in series.
Three identical resistors each 45 ohms are connected in parallel across a 60-V battery The current through or drawn from the battery is?
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
Two resistors are connected in a parallel to a batterywhat is the voltage across these two resistors?
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
Do additional resistors affect power?
Of course. Additional resistors change total resistance, which changes current, which affects power.
How is a circuit constructed with five resistors and a battery as shown?
A circuit with five resistors and a battery is constructed by connecting the resistors in series or parallel to create a closed loop for the flow of electric current from the battery through the resistors. The battery provides the energy for the current to flow through the resistors, which resist the flow of current. The arrangement of the resistors and the battery determines the overall resistance and current flow in the circuit.
How is a simple ohmmeter constructed?
A simple ohmmeter is constructed using a battery, a galvanometer, and a set of resistors. The battery supplies a constant voltage, while the galvanometer measures the current flowing through the circuit when a resistor is connected. The resistance is calculated using Ohm's Law (R = V/I), where V is the battery voltage and I is the current indicated by the galvanometer. The device may also include a scale or a dial to provide a direct reading of resistance values.
What is true about series connections of resistors?
The more resistance there is, the harder it is for current to flow. So the total resistance is the sum of all resistors in series.
How does the area of series resistors affect the overall resistance in a circuit?
The total resistance in a circuit with series resistors is the sum of the individual resistances. When more resistors are added in series, the total resistance increases because the current has to pass through each resistor, making it harder for the current to flow.
Do additional resistors affect current in a series circuit?
Yes, additional resistors affect current in a series circuit by increasing the total resistance, which decreases the total current.
Is a calculator a resistor?
No, but it has resistance. Everything has resistance to current flow. It's sole purpose is not to resist current. It likely has resistors in it though.
Three identical resistors each 45 ohms are connected in parallel across a 60-V battery The current through or drawn from the battery is?
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
Two resistors are connected in a parallel to a batterywhat is the voltage across these two resistors?
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
What is the current of a circuit that has two 5-ohm resistors and a 12 V battery?
If the two 5 ohm resistors were in series, then the current would be 1.2 amperes. If they were in parallel, then the current would be 4.8 amperes. Ohm's Law: Current = Voltage divided by Resistance RSeries = Summation1toN RN RPARALLEL = 1 / Summation1toN (1 / RN)
Do additional resistors affect power?
Of course. Additional resistors change total resistance, which changes current, which affects power.
Does the current remains the same in a series circuit despite the different values if the resistors in the circuit?
current in series depends on values of resistors. more resistance less current will flow through and viceversa
What are the differences between resistors connected in parallel and resistors connected in series, and how do these configurations affect the overall resistance in a circuit?
Resistors connected in parallel have the same voltage across them, while resistors connected in series have the same current passing through them. In a parallel configuration, the total resistance decreases as more resistors are added, while in a series configuration, the total resistance increases.
