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What is the PD across two resistors connected parallel to a battery of emf 6V?
The potential difference across two resistors connected in parallel to a battery with a potential difference of 6 volts is 6 volts. Kirchoff's Voltage Law: The signed sum of the voltage drops in a series circuit is zero. This means that that the two series circuits involving the battery and each resistor have the same voltage across each other, and the series circuit involving the two resistors have the same voltage across each other.
How do you turn off a series circuit?
Unscrew any one, and they will all go out. Its a series circuit, so Kirchoff's voltage law says that the sum of the voltage drops around the circuit must add up to zero. The open point is infinity ohms, so the voltage across that open point is equal to the source voltage, (Ohm's Law: Volts = Amps * Ohms), and the voltage across the relatively small ohms of each bulb must be zero. Zero volts = zero amps = zero power.
When two cells with the same voltage are connected in a series circuit what happens to the voltage?
There is addition of voltage. Dry cells have 1.5 volts irrespective of there size. if the cells are added as same polarity in series it will add if are parallel then voltage remains same
What is a series circuit that is used to produce a voltage source of desired magnitude from a higher voltage battery?
Such a circuit would be called a voltage divider.The circuit would consist of two or more resistors in series across a battery or other voltage source. Each resistor would drop a certain amount of voltage (proportional to its resistance), and by considering the voltage drops, the investigator could pick two points in the circuit from which to take (or "pick off") the desired voltage needed for a project. Let's look at just one example.If a 12 volt battery has two 1K ohm resistors in series across it, each resistor will drop 6 volts. By connecting wires from each end of one resistor, the 6 volts can be "picked off" and used to do something else. Certainly there are limitations concerning how much current can be drawn from the circuit (called loading the circuit), as the "diversion" of current around the resistor that is providing the voltage will change the voltage that is being picked off. But for small amounts of current, the voltage divider will work adequately.
What causes varying light bulb intensities on same circuit?
For a series circuit... Each bulb has different impedance (ohms) resulting in a different voltage drop across each. Remember Kirchoff's Current Law: The current at each point in a series circuit is the same. That same current, multiplied by the different voltage drops results in different powers (watts = amps * volts) for each bulb. For a parallel circuit. Again, each bulb still has different impedance. This time, the voltage drop is the same (Kirchoff's Voltage Law) but the current in each bulb is different. Same situation - different power in each bulb.
What is the voltage drop of a series circuit with four voltage drops of 30 volts?
there is 120V across the circuit.
What is the problem when you have 110-120 volt but when circuit is completed voltage drops to 30 volts?
A resistance in series with the circuit. It is most likely a wiring error, loose connection or load hooked in series instead of parallel.
If three lamps are connected in series to a 6 volt battery how many volts are impressed across each lamp?
In a parallel circuit, Voltage is constant through out the circuit. Thus, the voltage across each lamp is 6-volts.
Do parts of a series circuit have the same amount of volts?
No. Parts of a series circuit have the same amount of current, but not necessarily the same amount of voltage.
If 3 1.5 V cells were connected in series what would the total voltage of the circuit be What about in Parallel?
4.5 volts in series; 1.5 volts in parallel.
What is the PD across two resistors connected parallel to a battery of emf 6V?
The potential difference across two resistors connected in parallel to a battery with a potential difference of 6 volts is 6 volts. Kirchoff's Voltage Law: The signed sum of the voltage drops in a series circuit is zero. This means that that the two series circuits involving the battery and each resistor have the same voltage across each other, and the series circuit involving the two resistors have the same voltage across each other.
If three 6 volt batteries are connected in series the overall voltage in circuit is?
Regardless of the number and value of the resistors, total voltage drop in a series circuit will equal the voltage rise, or the applied voltage. Apply 6 volts to three series resistors and the sum of the voltage drops will be 6 volts. No mystery here. Think it through and it will lock in. To get you ready for more "advanced" analysis, Kirchhoff said the algebraic sum of the voltages in any closed loop is zero. Going all the way around a series circuit, we'd encounter the battery, and all the series resistors. The battery is a voltage rise, and the resistors are voltage drops. The polarity of a voltage rise is opposite that of a voltage drop. This means that when they are added algebraically, if they are equal, they will sum to zero. Work this with a battery connected across a single resistor to get a handle on it. You'll need the ideas to manage calculations in loops of parallel circuits. Remember that in any closed loop, the algebraic sum of the voltages is zero.
How does the voltage across a battery compare to the voltage across the light bulb?
Without a circuit diagram, there are more questions before answers. First, assuming no other components, there is wire resistance to consider. There is also minor resistance in each connection, and each switch contact. In any event, the sum of the voltage drops in any series ckt equals the voltage of the source. If the sum of the wire, contact, and other voltage drops was .2 volts, and the source was 12.6 volts, then the light bulb would have 12.4 volts applied to it.
How do you turn off a series circuit?
Unscrew any one, and they will all go out. Its a series circuit, so Kirchoff's voltage law says that the sum of the voltage drops around the circuit must add up to zero. The open point is infinity ohms, so the voltage across that open point is equal to the source voltage, (Ohm's Law: Volts = Amps * Ohms), and the voltage across the relatively small ohms of each bulb must be zero. Zero volts = zero amps = zero power.
How do you measur ampere?
You use an "amp gauge" to measure amps in an actual circuit. It is hooked in series with the load. It can be placed anywhere in the circuit as long as it is hooked in series. Mathematically, you have to know the resistance, or wattage and voltage of a circuit. Volts=amps*resistance or amps=volts/resistance, or resistance=volts/amps. Ohms law!
When two cells with the same voltage are connected in a series circuit what happens to the voltage?
There is addition of voltage. Dry cells have 1.5 volts irrespective of there size. if the cells are added as same polarity in series it will add if are parallel then voltage remains same
What happens to the energy as it goes around a series circuit?
What do you mean by energy? amps? Volts?, Either way if you have a series circuit with 3 loads in the circuit all voltage will be dropped proportionally to the loads resistance, if that makes any sense.
