About 48,000 BTU
You need to have load calculations done. Insulation, windows, location, outside temps, shade conditions, etc. will all affect the answer. For a shop with no windows and very good insulation or in a moderate climate, 48,000 btu may be sufficient. There are heating and cooling load worksheets available on the web if you know the R-value of your insulation and window type.
Consider the 2800va (v)olts x (a)mps the same as 2800 watts (at unity power factor). The formula for amps is A = W/E, 2800/120 = 23.33 amps.
In the weld area the steel is molten 2800 degrees F +. The arc can reach 5000 degrees F +. Surrounding areas anywhere from cold to 2800 degrees F.
No
To determine the appropriate electric cable size for a 7.5 kW, 3-phase motor operating at 2800 RPM and located 170 meters away, you need to consider the current draw and voltage drop. The current can be calculated using the formula: (I = \frac{P}{\sqrt{3} \times V \times \text{Power Factor}}). For a standard voltage of 400V and a typical power factor of 0.8, the current is approximately 11.5 A. Given the distance, a cable size of at least 4 mm² is generally recommended to limit voltage drop to acceptable levels (typically under 5%). However, local regulations and installation conditions should always be considered for precise determinations.
Please refer to this link it may help you: www.ebmpapst.co.uk/assets/PDF/technical%20library/Synchronous%20Speed.pdf
About 48,000 BTU You need to have load calculations done. Insulation, windows, location, outside temps, shade conditions, etc. will all affect the answer. For a shop with no windows and very good insulation or in a moderate climate, 48,000 btu may be sufficient. There are heating and cooling load worksheets available on the web if you know the R-value of your insulation and window type.
One roll is good for 4 squares (400 sq ft) so, 2800 / 400= 7
70% of 2800= 70% * 2800= 0.7 * 2800= 1,960
5% of 2800= 5% * 2800= 0.05 * 2800= 140
36% of 2800 = 36% * 2800 = 0.36 * 2800 = 1008
56020% of 2800= 20% * 2800= 0.20 * 2800= 560
89% of 2800= 89% * 2800= 0.89 * 2800= 2492
% rate:= 7/2800 * 100%= 0.0025 * 100%= 0.25%
2800
A typical delivery truck can hold around 2,000 to 4,000 gallons of heating oil, depending on the size and capacity of the tank.
2800/1
To find out how many hundreds go into 2800, you divide 2800 by 100. Doing the calculation, 2800 ÷ 100 equals 28. Therefore, there are 28 hundreds in 2800.