No
Consider the 2800va (v)olts x (a)mps the same as 2800 watts (at unity power factor). The formula for amps is A = W/E, 2800/120 = 23.33 amps.
In the weld area the steel is molten 2800 degrees F +. The arc can reach 5000 degrees F +. Surrounding areas anywhere from cold to 2800 degrees F.
Please refer to this link it may help you: www.ebmpapst.co.uk/assets/PDF/technical%20library/Synchronous%20Speed.pdf
To determine the appropriate electric cable size for a 7.5 kW, 3-phase motor operating at 2800 RPM and located 170 meters away, you need to consider the current draw and voltage drop. The current can be calculated using the formula: (I = \frac{P}{\sqrt{3} \times V \times \text{Power Factor}}). For a standard voltage of 400V and a typical power factor of 0.8, the current is approximately 11.5 A. Given the distance, a cable size of at least 4 mm² is generally recommended to limit voltage drop to acceptable levels (typically under 5%). However, local regulations and installation conditions should always be considered for precise determinations.
About 48,000 BTU You need to have load calculations done. Insulation, windows, location, outside temps, shade conditions, etc. will all affect the answer. For a shop with no windows and very good insulation or in a moderate climate, 48,000 btu may be sufficient. There are heating and cooling load worksheets available on the web if you know the R-value of your insulation and window type.
2800/2 = 1400
No. The water pump is designed for a specific RPM. It will not operate correctly, and will probably be damaged, if you attempt to operate it at twice the design RPM.
1400
To find half of 2800, you simply divide the number by 2. So, 2800 divided by 2 equals 1400. Therefore, half of 2800 is 1400.
1400 100% = 28000 10% = 2800 Half of that = 5% = 1400
get the 2800
To convert 1400 RPM to 2800 RPM using a pulley system, you would need to use a pulley ratio that doubles the speed. This can be achieved by using a smaller drive pulley on the motor (connected to the 1400 RPM source) and a larger driven pulley on the output shaft. The size ratio of the drive pulley to the driven pulley should be 1:2, meaning for every rotation of the drive pulley, the driven pulley makes two rotations, effectively doubling the RPM to 2800.
140000 * .02(2%) is equal to 2800
He saved $2800 because he spent $7000 - $4200 = $2800.
700, 1400, 2100, 2800, 3500, 4200, 4900 . . . to infinity.
280 560 840 1120 1400 1680 1960 2240 2520 2800
2/5 x 700 = 1400/5 = 2800/10 = 280