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What else can I help you with?
What is a maximum voltage across a resistor?
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
What is the voltage across the first ohm resistor?
if R4 is the only resistor (the load), then the drop would be the same as the energy source
How would you connect a resistor in order to reduce an LED's applied voltage?
You could use the voltage divider rule to reduce the voltage. Using two resistors in series, the input voltage will drop across each resistor by an amount that is proportionate to the values of the resistors. If the 1st resistor is 10K and the 2nd resistor is 100K, the voltage drop across the 10K will be 10 times LESS than that of the 100K resistor. The total voltage drop across both resistors will be equal to the supplied input voltage. Work out the ratio of voltage you need from the total input voltage and use 2 resistors will that give you the same ratio. Connect the LEDs in parallel with the resistor the gives you the voltage you want. Use a MM to measure the voltage across the resistor before wiring LEDs.
When resistors are connected in series in a circuit. what are the relationships between the voltage drops across the resistor and the currents through the resistors?
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
Three identical bulbs are connected in parallel across a 12-V battery If one of the bulbs were removed from its socket then the potential difference measured across the empty socket would be?
12V. Every resistor in a parallel circuit shares the same voltage. It is the current that gets divided.
What is a maximum voltage across a resistor?
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
Is it possible to apply voltmeter across a variable resistor?
Of course. A good voltmeter can be applied across anything, since its impedance is high and its presence has no effect on the operation of the circuit. When it's connected across a variable resistor, the voltmeter most likely reveals a changing voltage as the resistor is varied.
What is the voltage across the first ohm resistor?
if R4 is the only resistor (the load), then the drop would be the same as the energy source
Why do resistor voltage decrease while capacitor discharges?
The reason why resistor voltage decreases while a capacitor discharges is because the resistor acts like a source of electrical energy. As the capacitor discharges, it draws energy from the resistor, which causes the voltage across the resistor to decrease. This is because the capacitor is acting like a drain, and is taking energy out of the resistor, thus causing the voltage across the resistor to decrease. The resistor and capacitor work together in order to create a discharge circuit. This is done by connecting the capacitor to the resistor, and then to a voltage source. The voltage source supplies the energy to the resistor, and then the resistor transfers this energy to the capacitor. As the capacitor discharges, it takes energy from the resistor, which causes the voltage across the resistor to decrease. In order to understand this process better, it is important to understand the basics of Ohm's Law. Ohm's Law states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance. As the capacitor discharges, it takes energy from the resistor, which means that the current through the resistor decreases, and therefore the voltage across the resistor will also decrease.
How would you connect a resistor in order to reduce an LED's applied voltage?
You could use the voltage divider rule to reduce the voltage. Using two resistors in series, the input voltage will drop across each resistor by an amount that is proportionate to the values of the resistors. If the 1st resistor is 10K and the 2nd resistor is 100K, the voltage drop across the 10K will be 10 times LESS than that of the 100K resistor. The total voltage drop across both resistors will be equal to the supplied input voltage. Work out the ratio of voltage you need from the total input voltage and use 2 resistors will that give you the same ratio. Connect the LEDs in parallel with the resistor the gives you the voltage you want. Use a MM to measure the voltage across the resistor before wiring LEDs.
Two 20K resistors R1 and R2 are in series across a 100 volt supply what would the voltage be across R1 if measured with a digital voltmeter with an internal resistance of 1M?
The voltage across R1 would be 50 volts. This is because the voltage divider rule states that the voltage across each resistor in a series circuit is proportional to its resistance relative to the total resistance in the circuit. In this case, since both resistors are the same (20K), the voltage across each resistor will be half of the total supply voltage.
If the volts going in equals 5 and there is a resistance that equals 6 what would be the volts coming out?
The question is a bit ambiguous, but I will try to address it. If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it). If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.
What is the difference between an inductive low pass filter and a capacitive low pass filter?
Where you are measuring. A simple filter will be two elements - a capacitor or inductor and a resistor. A capacitor will tend to "trap" low frequencies. In the case of a lowpass filter made of a capacitor and resistor, the output voltage will be measured across the capacitor. Inductors are the opposite, so the output would be across the resistor.
When resistors are connected in series in a circuit. what are the relationships between the voltage drops across the resistor and the currents through the resistors?
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
The voltage drop across a resistor is 1.0 V for a current of 3.0 A in the resistor what is the current that will produce a voltage drop of 9.0 V across the resistor?
Using Ohm's Law (V = I * R), we can rearrange the formula to solve for the resistance. For the first scenario: 1.0 V = 3.0 A * R R = 1.0 V / 3.0 A = 0.33 ohms Now with a voltage drop of 9.0 V: 9.0 V = I * 0.33 ohms I = 9.0 V / 0.33 ohms = 27.27 A
Three identical bulbs are connected in parallel across a 12-V battery If one of the bulbs were removed from its socket then the potential difference measured across the empty socket would be?
12V. Every resistor in a parallel circuit shares the same voltage. It is the current that gets divided.
What would you do to measure the change in energy per unit charge across a resistor?
To measure the change in energy per unit charge across a resistor, you can use the formula E = VQ, where E is the energy, V is the voltage across the resistor, and Q is the charge passing through it. By measuring the voltage across the resistor and the charge passing through it, you can calculate the energy per unit charge.
