Try the mathematics and you will see how.
For f(x) = ∫x dt, where x is a square wave function, f(x) will be a triangle wave function.
Also try what happens where x is a triangle wave function!
The output of a Miller integrator is a triangular waveform. This occurs because the integrator continuously sums the input signal over time, producing a ramp-like output that rises and falls based on the input's characteristics. If the input is a square wave, for instance, the output will oscillate between linear ramps in opposite directions, resulting in a triangular shape.
Triangular wave
When a low pass filter is used with a sine wave input, the output is also a sine wave. The output will be reduced in amplitude and phase shifted when the frequency is high, but it is still a sine wave. This is not the case for square or triangular wave inputs. For non-sinusoidal inputs the circuit is called an integrator.
To design a simple integrator with an op amp, place a resistor and capacitor in series in the feedback loop, between output and inverting input. Place another resistor from circuit input to the inverting input. Ground the non-inverting input. The current through the input resistor will be balanced with the current through the feedback resistor. Since there is a capacitor also, the voltage slope at the output will be proportional to the current. If you want the capacitor to discharge faster in one direction, you can place a diode (and optional resistor) across the feedback resistor. This works because the capacitor resists a change in voltage, proportional to current, and inversely proportional to capacitance. The equation is dv/dt = i/c. This means that dv/dt is linear with constant i and c. In this configuration, a constant current input will be balanced with a linear voltage ramp on the output, limited only by the range of the op amp. Constrast this with a simple RC circuit - with constant voltage, the RC circuit will exhibit a logarithmic output. If, for instance, you were to drive this circuit with a square wave, the output would be triangular. With the diode, the output would be sawtooth.
It is a square shape of the wave applied at the input of the circuitry> ANSWER: A square wave is basically two rectangular power input It is called square to differentiate from other sources triangular sawtooth and so forth.
The output of a Miller integrator is a triangular waveform. This occurs because the integrator continuously sums the input signal over time, producing a ramp-like output that rises and falls based on the input's characteristics. If the input is a square wave, for instance, the output will oscillate between linear ramps in opposite directions, resulting in a triangular shape.
Triangular wave
When a low pass filter is used with a sine wave input, the output is also a sine wave. The output will be reduced in amplitude and phase shifted when the frequency is high, but it is still a sine wave. This is not the case for square or triangular wave inputs. For non-sinusoidal inputs the circuit is called an integrator.
If you use a square wave as input to an integrator circuit, the output will be a triangle wave.
The monostable provides a square wave, which can be converted into a triangular wave by putting it through an integrator.
because of charging and discharging of capacitor present in the circuit. beacause capacitor charges exponentially. akshay dabhane
To design a simple integrator with an op amp, place a resistor and capacitor in series in the feedback loop, between output and inverting input. Place another resistor from circuit input to the inverting input. Ground the non-inverting input. The current through the input resistor will be balanced with the current through the feedback resistor. Since there is a capacitor also, the voltage slope at the output will be proportional to the current. If you want the capacitor to discharge faster in one direction, you can place a diode (and optional resistor) across the feedback resistor. This works because the capacitor resists a change in voltage, proportional to current, and inversely proportional to capacitance. The equation is dv/dt = i/c. This means that dv/dt is linear with constant i and c. In this configuration, a constant current input will be balanced with a linear voltage ramp on the output, limited only by the range of the op amp. Constrast this with a simple RC circuit - with constant voltage, the RC circuit will exhibit a logarithmic output. If, for instance, you were to drive this circuit with a square wave, the output would be triangular. With the diode, the output would be sawtooth.
It is a square shape of the wave applied at the input of the circuitry> ANSWER: A square wave is basically two rectangular power input It is called square to differentiate from other sources triangular sawtooth and so forth.
beacause the supply is the input and the output is the square wave
a phase shifted sine wave of a different amplitude.
Oh, dude, if a sine wave is the input to a NOT gate, the output will be the inverted sine wave. It's like flipping the wave upside down, you know? So, if the input is high, the output will be low, and vice versa. It's just how the NOT gate rolls, man.
The output frequency of a full wave rectifier will be twice the input frequency. This is because full wave rectifiers process both the positive and negative cycles of the input signal, effectively doubling the frequency in the output waveform.