No. V =Voltage, I =current, and R =resistancein the simple equation: V=I*R. As well, V/I=R, and. V/R=Iso Current is voltage divided by resistance
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
Where V=stands for voltage, I=stands for current and R=stands for resistance. voltage=current multiplied by resistance so, by transposition, resistance=voltage divided by current. or R=V/I, R=9/3 The resistance is 3 ohms.as by ohm's law, v=irr = v/itherefore the resistance is 9/3=3 ohms
Here is the formula you use. I = E/R. I = amperage, E = volts, R = resistance in ohms.
You can not change amp's amps is the result of voltage and resistance. Current is represented by I, Voltage is represented by E and Resistance is represented by R in ohms law. I=E/R, R=E/I and E=IxR the I is never a variable
I=V/R The smaller the resistance the greater the amperage.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
To calculate the amperage, you need to know the resistance in the circuit. Amperage is calculated using Ohm's Law: Amperage (A) = Voltage (V) / Resistance (R). Without knowing the resistance, we cannot determine the amperage.
To answer this question the resistance of the load is needed. I = E/R.
The two main factors that determine how much amperage will flow in a circuit are the voltage of the source supplying the electricity and the resistance in the circuit. According to Ohm's Law, the amperage (current) in a circuit is equal to the voltage divided by the resistance (I = V/R).
To calculate amperage using Ohm's Law (I = V/R), you need to know the resistance (R). In this case, with a voltage of 120V and frequency of 60Hz, you can't determine amperage without knowing the resistance of the circuit.
The amperage in the circuit can be calculated using Ohm's Law: Amperage = Voltage / Resistance. Plugging in the values, we get Amperage = 110V / 7ohms = 15.71A. Therefore, the circuit would have approximately 15.71 amps of current flowing through it.
No. V =Voltage, I =current, and R =resistancein the simple equation: V=I*R. As well, V/I=R, and. V/R=Iso Current is voltage divided by resistance
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
The equation for the three values in the question will give the definite answer.Amperage (I) is equal to the voltage (E) divided by the resistance (R).I= E / R So as you can see the answer is True.Example: 10 Volts and 50 Ohms in a circuit will have a current of .2 Amperes flowing through it. 10 / 50 = .2You can also rearrange the equation to find the other two:E= R * ER= E / I
Turn off circuit. Then you can use a meter set for resistance, clip onto both ends of the resistor, meter will display the resistance in ohms.If you know the voltage and amperage you can use Ohm's Law: E=IRR=E/IR is resistance, E is voltage, and I is current (amperage)