0
True or false if the voltage and resistance of a circuit stay constant the amperage can never change?
The equation for the three values in the question will give the definite answer.
Amperage (I) is equal to the voltage (E) divided by the resistance (R).
I= E / R So as you can see the answer is True.
Example: 10 Volts and 50 Ohms in a circuit will have a current of .2 Amperes flowing through it. 10 / 50 = .2
You can also rearrange the equation to find the other two:
E= R * E
R= E / I
What else can I help you with?
What 2 Factors Determine How Much Amperage Will Flow?
The two main factors that determine how much amperage will flow in a circuit are the voltage of the source supplying the electricity and the resistance in the circuit. According to Ohm's Law, the amperage (current) in a circuit is equal to the voltage divided by the resistance (I = V/R).
How many amp is 21 volts?
To calculate the amperage, you need to know the resistance in the circuit. Amperage is calculated using Ohm's Law: Amperage (A) = Voltage (V) / Resistance (R). Without knowing the resistance, we cannot determine the amperage.
How many amps does a circuit with 110 volts and a resistance of 7ohms have?
The amperage in the circuit can be calculated using Ohm's Law: Amperage = Voltage / Resistance. Plugging in the values, we get Amperage = 110V / 7ohms = 15.71A. Therefore, the circuit would have approximately 15.71 amps of current flowing through it.
What does volts times amperage equal?
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
How much does amperage drop with distance?
Amperage drop with distance depends on the resistance of the conductor and the load. As distance increases, resistance increases, leading to higher voltage drop. This can result in lower amperage at the end of the circuit compared to the source. Use Ohm's Law (V=IR) to calculate the amperage drop based on the resistance and distance.
Doubling the resistance in a circuit will increase or decrease amperage?
If voltage remains constant and resistance is increased, the amperage will decrease per Ohm's Law.
What 2 Factors Determine How Much Amperage Will Flow?
The two main factors that determine how much amperage will flow in a circuit are the voltage of the source supplying the electricity and the resistance in the circuit. According to Ohm's Law, the amperage (current) in a circuit is equal to the voltage divided by the resistance (I = V/R).
What tool can be used to test voltage resistance and amperage in a circuit?
A multimeter.
If the resistance in a circuit is doubled while the voltage remains the constant the current is?
It is halved. coz voltage=current * resistance
In a AC parallel circuit which is constant voltage or resistance?
Voltage will be constant. Resistance is dependent on the components in the circuit. Source: Electronics Technician for the US Govt
If the voltage applied to a circuit remains constant and the resistance in the circuit is increased the current will?
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
How does current vary with the resistance in the circuit if the voltage is constant?
Inversely. As resistance increases, current dereases; given that the applied voltage is constant.
How to figure amps in an electrical circuit?
To figure out the amps in an electrical circuit, you can use Ohm's Law, which states that Amps Volts / Resistance. Measure the voltage across the circuit and the resistance of the components in the circuit, then divide the voltage by the resistance to calculate the amperage.
Does the amperage double when you double both the current and the voltage in a circuit?
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
Will doubling the resistance in a circuit halve the current if voltage is held constant?
If resistance is halved while voltage remains constant, the current will double.
What is the relationship between current and resistance in a circuit when the voltage is kept constant?
In a circuit with constant voltage, the relationship between current and resistance is inversely proportional. This means that as resistance increases, the current flowing through the circuit decreases, and vice versa.
If the resistance in a circuit is doubled while the voltage remains constant the current does what?
If resistance is doubled in a circuit with constant voltage, Ohm's Law (V=IR) states that current (I) would be halved since the voltage is constant. This is because the relationship between resistance and current is inversely proportional.
