It is known as resonance and there is maximum voltage drop at this point.
In an electric generator, the function of a capacitor is to provide reactive power and improve the power factor of the generator. When a generator is connected to a load, the load may have a combination of resistive, inductive, and capacitive components. Inductive loads can cause the power factor of the generator to decrease, resulting in lower efficiency and voltage regulation. By adding a capacitor in parallel with the generator, the reactive power generated by the capacitor can offset the reactive power of the inductive load, leading to improved power factor correction. This helps to enhance the efficiency of power transfer and stabilizes the voltage. The capacitor absorbs and supplies reactive power, reducing the strain on the generator and ensuring a steady and efficient supply of electrical energy.
In the basic configuration, a capacitor is constructed with two parallel conductor plates with a layer of insulating material in between. When the cap is hooked up to the AC power supply, the voltage (v) across the plates and the charge (q) induced on the plates follow this capacitance expression: C = dq/dv or i = C dv/dt, where C is determined by the properties of the insulating material and the geometry of the cap (in the case of the parallel plates, the separation between the two electrodes (t). For the parallel plates, C can be written as (dielectric constant * plate area / t). Electrically, the change in the charge induced on the plates (dq), is directly related to the change in voltage difference (dv) between the two plates, since C is a constant. Theoretically, no energy is lost by charging and discharging the cap with an AC current. When the cap absorbs electrical energy from the power supply, it stores the energy in the electric field in the insulator. When discharging, the cap gives the stored energy back to the circuit -- hence, no energy loss. In a circuit, we use the cap to prolong/smoothen/resist any voltage change in time or to absorb a sudden energy surge (electrostatic discharge and power-line glitches, for example).
'Power' is not 'consumed'; it is simply a 'rate' -the rate at which 'energy' is being consumed.No energy is being consumed by a load which is either purely inductive or purely capacitive so, for such loads, the rate of energy consumption, or the power, would be theoretically be zero. However, purely inductive or capacitive circuits only exist in theory, and all circuits exhibit some degree of resistance, so you will never have a condition under which the power of an a.c. circuits truly becomes zero.
Series resonance is called voltage resonance because at resonance frequency in a series RLC circuit, the impedance of the inductor and capacitor cancel each other out, resulting in minimum impedance. This causes the total voltage across the circuit to be maximized, leading to a peak in voltage across the components at resonance. This phenomenon is known as voltage resonance because it results in a maximum voltage across the circuit at that specific frequency.
Submarine power cables work on voltages of 400 kV or more, often with DC because they are linking power grids that are not synchronised.Submarine communications cables now work with fibre-optics so the signals are modulated light-waves.Additional AnswerFurther to the original answer, another reason for using direct current for submarine cables is to eliminate capacitive currents that would flow if a.c. were used instead. The closeness of the submarine-cable's cores results in relatively-high levels of capacitance between each core and, with a.c., this would represent a capacitive load resulting in a continuous capacitive current along the cable. Such currents flow in all underground a.c. cables but, due to the length of most submarine cables, the capacitive current can be unnecessarily high.
For resonance to occur in an electrical circuit with a reactive element, the reactive element's reactance needs to be equal and opposite to the circuit's impedance. This occurs when the capacitive and inductive reactances cancel out, resulting in a net impedance that is purely resistive. At this point, maximum current flows through the circuit, enhancing certain frequencies.
Inductive and capacitive elements store energy. When first switched on, they attempt to charge up, which causes these transient voltages. When the power turned on rather a load is put on, it draws the load current, by which the IR drop iccurs, resulting into voltage drop.
C = capacitance, f = frequency ===> Capacitive reactance = 1 / [ 2(pi)fC ] 663 = 1 / [ 2(pi)(60)C ] 663 x 2 x pi x 60 x C = 1 C = 1 / (663 x 2 x pi x 60) = 1 / (663 x 120 x pi) = 1 / 249,945.1 = 4 x 10-6 = 4 microfarads (almost exactly)
In an electric generator, the function of a capacitor is to provide reactive power and improve the power factor of the generator. When a generator is connected to a load, the load may have a combination of resistive, inductive, and capacitive components. Inductive loads can cause the power factor of the generator to decrease, resulting in lower efficiency and voltage regulation. By adding a capacitor in parallel with the generator, the reactive power generated by the capacitor can offset the reactive power of the inductive load, leading to improved power factor correction. This helps to enhance the efficiency of power transfer and stabilizes the voltage. The capacitor absorbs and supplies reactive power, reducing the strain on the generator and ensuring a steady and efficient supply of electrical energy.
In the basic configuration, a capacitor is constructed with two parallel conductor plates with a layer of insulating material in between. When the cap is hooked up to the AC power supply, the voltage (v) across the plates and the charge (q) induced on the plates follow this capacitance expression: C = dq/dv or i = C dv/dt, where C is determined by the properties of the insulating material and the geometry of the cap (in the case of the parallel plates, the separation between the two electrodes (t). For the parallel plates, C can be written as (dielectric constant * plate area / t). Electrically, the change in the charge induced on the plates (dq), is directly related to the change in voltage difference (dv) between the two plates, since C is a constant. Theoretically, no energy is lost by charging and discharging the cap with an AC current. When the cap absorbs electrical energy from the power supply, it stores the energy in the electric field in the insulator. When discharging, the cap gives the stored energy back to the circuit -- hence, no energy loss. In a circuit, we use the cap to prolong/smoothen/resist any voltage change in time or to absorb a sudden energy surge (electrostatic discharge and power-line glitches, for example).
A:The inductor does not allow ac signal to pass through. It blocks ac and passes dc. If the switch is open, then the ac signal wont pass. If the switch is closed, then the ac signal will pass through the switch.AnswerIt is incorrect to say that an inductor 'does not allow' the passage of an alternating current. An a.c. current will pass through an inductor, although the inductor will limit the value of that current due to the inductor's inductive reactance. Inductive reactance, which is expressed in ohms, is directly-proportional to the inductance of the inductor and to the frequency of the supply. The value of the current is determined by dividing the supply voltage by the inductive reactance of the inductor.If the switch is connected in parallel with the inductor, then closing the switch will apply a direct short circuit across the inductor, and the resulting short-circuit current will cause the circuit's protective device (fuse or circuit breaker) to operate.
The windings of a transformer have both resistance and inductance. When you apply an AC voltage to the primary winding, the opposition to current flow is a combination of resistance and inductive reactance; although the resistance of the winding is relatively low, its inductive reactance is high. The resulting impedance (the vector sum of resistance and inductive reactance) will, therefore, be high and the resulting current will be low.If, on the other hand, you applied a DC voltage to the winding, the only opposition will be the low resistance of the winding. So, if the value of DC voltage is roughly the same as the rated AC voltage, a large value of current would result -high enough to probably burn out the winding.Since transformers work on the principle of mutual induction, a fluctuating magnetic field is necessary to induce a voltage into the secondary winding. Since a fluctuating magnetic field requires a fluctuating current, a transformer will only work if an AC voltage is applied to its primary winding.So, not only will a transformer not work when a DC voltage is applied to its primary winding, it will probably burn out the primary winding.
'Power' is not 'consumed'; it is simply a 'rate' -the rate at which 'energy' is being consumed.No energy is being consumed by a load which is either purely inductive or purely capacitive so, for such loads, the rate of energy consumption, or the power, would be theoretically be zero. However, purely inductive or capacitive circuits only exist in theory, and all circuits exhibit some degree of resistance, so you will never have a condition under which the power of an a.c. circuits truly becomes zero.
Ferroresonance is a phenomenon that can occur in electrical systems when there is a combination of non-linear characteristics from inductive elements and capacitive elements, resulting in high voltages and potential damage to equipment. It can occur in power systems during switching operations or when equipment is disconnected or connected abruptly. Mitigation measures include the use of resistors, damping circuits, and proper system design.
Anemia is the condition resulting from deficiencies of various nutrients. Anemia is also a condition in which the body does not have enough healthy red blood cells.
Calories
Osteoporosis