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When modulation frequency is doubled modulation index also doubled in case of FM or pm or am?
In Frequency Modulation (FM), if the modulation frequency is doubled, the modulation index does not necessarily double; it depends on the amplitude of the modulating signal. In Amplitude Modulation (AM), the modulation index is defined as the ratio of the peak amplitude of the modulating signal to the carrier amplitude, so it remains unchanged with varying modulation frequency. For Phase Modulation (PM), similar to FM, the modulation index is influenced by the amplitude of the modulating signal and does not inherently double with the modulation frequency. Thus, modulation frequency and modulation index are not directly linked in this way for FM, PM, or AM.
The resonance frequency of 1200 What is the resonance frequency if the inductance L is doubled?
1200/sqrt(2) = 848.5 (rounded)
How will the resonance frequency change If the resistance in an RLC circuit is doubled but he capacitance and inductance are unchanged?
For to keep the resonant frequancy constant L*C has to stay same. Lets say if you double L you have to divide C by 2 to keep the same resonant frequency. If only L increases Resonant frequency decrease, this is same for C.
If the resistance in a circuit is doubled while the voltage remains the constant the current is?
It is halved. coz voltage=current * resistance
What happens to the capacitive reactance when the frequency is doubled?
DATE: 17-MAY-12 THE CAPACITIVE REACTANCE VARIES INVERSELY WITH THE AMOUNT OF THE PRODUCT OF MAGNITUDE OF THE SUPPLY FREQUENCY, TWICE THE VALUE OF CONSTANT PI AND THE MAGNITUDE OF CAPACITANCE. IN OTHER WORDS, EVERY TIME YOU INCREASE ANY OF THESE FACTORS OR IF SAY YOU FIX THE VALUE OF CAPACITANCE TO SAY 1 MICROFARAD AND OTHER FACTOR (i.e. 2 x PI) AS CONSTANT ALSO, BUT THEN WHEN DOUBLING THE FREQUENCY, SO THEN THE EFFECT TO THE CAPACITIVE REACTANCE WILL BE INVERSELY OR HALVED. THE MORE YOU INCREASE THE FREQUENCY, THE SMALLER THIS VALUE WILL BE. WHICH IN EFFECT ALLOWING MORE HIGH FREQUENCY CURRENT OR VOLTAGE TO PASS THRU THE CIRCUIT. AND THE REVERSE IS TRUE, MEANING ONCE YOU ALLOW LOW FREQUENCY CURRENT, THEN THE CAPAICTIVE REACTANCE WILL INCREASE AS A RESULT. BY FMSJr. / ABU DHABI, UAE
When modulation frequency is doubled modulation index also doubled in case of FM or pm or am?
In Frequency Modulation (FM), if the modulation frequency is doubled, the modulation index does not necessarily double; it depends on the amplitude of the modulating signal. In Amplitude Modulation (AM), the modulation index is defined as the ratio of the peak amplitude of the modulating signal to the carrier amplitude, so it remains unchanged with varying modulation frequency. For Phase Modulation (PM), similar to FM, the modulation index is influenced by the amplitude of the modulating signal and does not inherently double with the modulation frequency. Thus, modulation frequency and modulation index are not directly linked in this way for FM, PM, or AM.
When modulating freq is doubled then modulating index is halved and modulating voltage remains constant system is?
It's Angle modulated system where the amplitude remains constant & frequency & phase varies with respect to modulating signal.
If a wave is moving at a constant speed and the wavelength is doubled what will happen to the frequency?
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
What happens to the speed of a wave if the amplitude is doubled and the frequency holds constant?
If the amplitude of a wave is doubled while the frequency remains constant, the speed of the wave will not change. The speed of a wave is determined by the medium through which it is traveling, not by its amplitude or frequency.
What happens to the wavelength of a wave when the frequency of the wave is doubled?
When the frequency of a wave is doubled, the wavelength is halved. This is because the speed of a wave is constant in a given medium, so an increase in frequency results in a decrease in wavelength to maintain a constant speed.
If the frequency of a wave traveling in a rope is doubled what will happen to the speed of the wave?
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
What happens to the wavelength if the frequency is doubled?
If the frequency is doubled, the wavelength of the wave will be halved. This is because the speed of the wave remains constant, so as frequency increases, the wavelength decreases to maintain that constant speed.
Is the stopping voltage doubled or more than doubled if frequency of lightwave is doubled under the condition where intensity is constant?
More than doubled. The stopping voltage is the photon energy minus the work function: hv - W Doubling the photon energy creates a new stopping voltage of: 2 hv - W > 2 (hv - W)
If a wave is traveling at a certain speed and its frequency is doubled what happened to the wavelength?
If the frequency is doubled, the wavelength is halved. This is because the speed of the wave remains constant, as determined by the medium it is traveling through. The wavelength and frequency of a wave are inversely related according to the equation: speed = frequency x wavelength.
If the frequency is doubled then for waves what would be the wavelength and vlocity?
Frequency = Velocity divided by wavelength. So if frequency is doubled that means velocity is doubled but the wavelength is halved. You can see this by keeping wavelength a constant : If Frequency =1 and Wavelength= 1 1= Velocity/1 Velocity=1 If Frequency =2 and Wavelength= 1 2= Velocity/1 Velocity =2 OR keeping Velocity constant: If Frequency =1 and Velocity= 1 1= 1/Wavelength Wavelength =1 If Frequency =2 and Velocity= 1 2= 1/Wavelength Wavelength=1/2
What happens to the wavelength of a wave on a string when the frequency is doubled (tension remains the same)?
When the frequency of a wave on a string is doubled, the wavelength decreases. This relationship is described by the wave equation ( v = f \lambda ), where ( v ) is the wave speed, ( f ) is the frequency, and ( \lambda ) is the wavelength. Since the tension remains constant, the wave speed also remains constant, so if the frequency increases, the wavelength must decrease in order to maintain the same wave speed. Specifically, if the frequency is doubled, the wavelength is halved.
What happens to the wavelength of a wave when the frequency of the wave is doubled but the wave speed stays the same?
If the frequency of a wave is doubled while the wave speed remains constant, the wavelength of the wave will be halved. This is because wavelength and frequency are inversely proportional in a wave, so when one doubles, the other is halved to keep the wave speed constant.
