That depends on both the input signal and the type of amplifier the transistor is used in.
pulse of positive voltage is not indicate to zero
AM wave is produced by applying the modulating voltage to the base of a transistor amplifier.
A bipolar junction transistor (BJT) can be used as a voltage amplifier by operating it in the active region, where it can increase the voltage of an input signal. In this configuration, a small input voltage applied between the base and emitter controls a larger current flowing from the collector to the emitter. The output voltage is taken across a load resistor connected to the collector, and the amplified output can be significantly higher than the input. The gain, or amplification factor, depends on the transistor's characteristics and the configuration of the circuit, such as common-emitter or common-collector arrangements.
The voltage gain (Av) of a transistor amplifier can be calculated using the formula ( Av = \frac{V_{out}}{V_{in}} ). In this case, the output voltage is 5 V rms and the input voltage is 250 mV rms (which is 0.25 V). Therefore, the voltage gain is ( Av = \frac{5}{0.25} = 20 ). This means the amplifier has a voltage gain of 20.
A simple, 1 transistor single stage amplifier can be made using several resistors to bias a NPN or PNP transistor into its' linear operating region. With this done, a small voltage signal applied to the input of the amplifier will have the voltage amplified at the output in a linear fashion. I'm not sure what your question is; if this does not answer it let me know.
as voltage amplifiercurrent followeri am yoges
depends on the circuit it is used in:CE/CS is inverting voltage amplifierCC/CD is noninverting current amplifierCB/CG is noninverting voltage amplifier
Voltage amplifier
No voltage gain
the common collector can use as voltage buffer
pulse of positive voltage is not indicate to zero
AM wave is produced by applying the modulating voltage to the base of a transistor amplifier.
If inceres the base voltage of transistor them it may be burn . The base volt may be 0.8v to 1.8 If it use as a amplifier
the out put voltage will be much grater then the input voltage.
A bipolar junction transistor (BJT) can be used as a voltage amplifier by operating it in the active region, where it can increase the voltage of an input signal. In this configuration, a small input voltage applied between the base and emitter controls a larger current flowing from the collector to the emitter. The output voltage is taken across a load resistor connected to the collector, and the amplified output can be significantly higher than the input. The gain, or amplification factor, depends on the transistor's characteristics and the configuration of the circuit, such as common-emitter or common-collector arrangements.
The voltage gain (Av) of a transistor amplifier can be calculated using the formula ( Av = \frac{V_{out}}{V_{in}} ). In this case, the output voltage is 5 V rms and the input voltage is 250 mV rms (which is 0.25 V). Therefore, the voltage gain is ( Av = \frac{5}{0.25} = 20 ). This means the amplifier has a voltage gain of 20.
A simple, 1 transistor single stage amplifier can be made using several resistors to bias a NPN or PNP transistor into its' linear operating region. With this done, a small voltage signal applied to the input of the amplifier will have the voltage amplified at the output in a linear fashion. I'm not sure what your question is; if this does not answer it let me know.