The resistance of a resistor will be numerically equal to its resistivity when the resistor's dimensions (length and cross-sectional area) are such that the resistance ( R ) is calculated using the formula ( R = \frac{\rho L}{A} ) and the units align accordingly. Specifically, this occurs when the length ( L ) of the resistor is equal to its cross-sectional area ( A ). In such a case, ( R ) would equal ( \rho ) if they are expressed in compatible units.
Internal resistance is approximately equal to 94.667
in a parallel circuit resistance decreases increasing the current.
every inductor has some resistance. In circuit diagram, ideal inductor is shown in series with a resistor(value being equal to coil's resistance) to make analysis easy.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
True. When two resistors of equal value are connected in parallel, the total power dissipated by the circuit is indeed the sum of the power dissipated by each resistor. Since they have the same resistance and are subjected to the same voltage, each resistor will dissipate the same amount of power, and their combined power will equal twice that of one resistor.
Take measurements of resistances of various lengths of a wire of constant diameter. Make a graph of resistance against length / cross-sectional area of wire. The gradient of the straight line section will be equal to the resistivity of the wire.
I am not sure how the two objects of equal resistance are supposed to be connected. But for a current to flow, for example across a resistor, there must be a voltage difference between the terminals of this resistor.
The rule for voltage across each resistor in a series circuit is that the total voltage supplied by the source is equal to the sum of the voltage drops across each resistor. In a parallel circuit, the voltage across each resistor is the same and equal to the source voltage.
The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
Internal resistance is approximately equal to 94.667
in a parallel circuit resistance decreases increasing the current.
every inductor has some resistance. In circuit diagram, ideal inductor is shown in series with a resistor(value being equal to coil's resistance) to make analysis easy.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
Ohm so correctly said: Voltage divided by current equals resistance. Voltage divided by current will tell you the value of a circuit's resistance. But resistance is not affected by either voltage or current. It is determined by the length, cross-sectional area, and resistivity (type of conducting material) of the conductor. Resistivity is, in turn, affected by temperature. So voltage divided by current tells you what the resistance happens to be - changes in voltage or current do not affect resistance.
No. You have to consider the inductor and the capacitor. Impedance of RLC circuit is equal to to the Value of Resistor Only AND Only on Resonate frequency. otherwise u have to cnsider resistance inductance and capacitance together in series.
Resistivity is equal to the product or resistance n area over divided over length ....is dimension is [m^1 l^3 t^-4 a^-3]