The ternary conditional operator:
x = a ? b : c;
This is the literal equivalent of the following if statement:
if (a) {
x = b;
} else {
x = c;
}
Note that a, b and c are all expressions (or compound expressions). Expression a must be a Boolean expression (evaluating true or false) while expressions b and c must be implicitly convertible to x's data type.
A real-world example:
// Return the larger of any two integers
int max (int a, int b) {
return a>b ? a : b;
}
The following program implements a user-defined class for rational numbers, including operator overloads for all arithmetic operations (+, -, * and /). Note that the class does not handle 0/n fractions properly because the reciprocal of 0/n is n/0 which is an invalid fraction with undefined value. The problem is that 0/n fractions are perfectly valid (1/2 - 1/2 = 0/2) so you need to cater for them (they simplify to zero), but you cannot divide by them. It is left as an exercise for the reader to provide handlers to cater for this type of exception. #include<iostream> #include<string> #include<sstream> // GCF: greatest common factor (AKA: GCD, greatest common divisor) int gcf (int a, int b) { // Recursive Euclid algorithm. return (b != 0 ) ? gcf (b, a % b) : a; } // LCM: least common multiple int lcm(int a, int b) { return (b / gcf (a, b)) * a; } // Class to store rational numbers (fractions). class rational { friend std::ostream& operator<< (std::ostream&, const rational&); private: int m_p; int m_q; public: rational (const int = 1, const int = 1); rational (const rational&); rational (const std::string& str); rational (const char* c_str); rational& operator= (const rational&); rational& operator= (const std::string&); rational& operator= (const char*); rational& operator-= (const rational&); rational& operator*= (const rational&); rational& operator/= (const rational&); rational& operator+= (const rational&); rational operator- (const rational&); rational operator* (const rational&); rational operator/ (const rational&); rational operator+ (const rational&); rational reciprocal() const; rational& simplify (); rational& unsimplify (int multiple); bool operator slash_pos) { std::string p = str.substr (0, slash_pos++); std::string q = str.substr (slash_pos, str.size()-slash_pos); std::stringstream ssp (p); std::stringstream ssq (q); int ip; int iq; if (ssp >> ip && ssq >> iq && iq != 0) { m_p = ip; m_q = iq; return *this; } } } return *this; } // Equality operator. bool rational::operator== (const rational& other) const { // Simplify both fractions before comparing. rational copy (*this); rational temp (other); copy.simplify(); temp.simplify(); return copy.m_p==temp.m_p && copy.m_q==temp.m_q; } // Return the reciprocal by value (swap numerator/denominator) rational rational::reciprocal() const { return rational (m_q, m_p); } // Simplifies the fraction. rational& rational::simplify() { // Simplify the sign. if (m_q<0) { m_p *= -1; m_q *= -1; } int factor = gcf (this->m_p, this->m_q); this->m_p /= factor; this->m_q /= factor; return *this; } // Usimplifies the fraction (use given denominator) rational& rational::unsimplify (int denominator) { this->m_p *= denominator / m_q; this->m_q = denominator; return *this; } // Test drive the rational class. int main() { // Test arithmetic. rational a = "1/2"; rational b (2, 5); // e.g., "2/5" std::cout << a << " + " << b << " = " << a + b << std::endl; std::cout << a << " - " << b << " = " << a - b << std::endl; std::cout << a << " * " << b << " = " << a * b << std::endl; std::cout << a << " / " << b << " = " << a / b << std::endl; // Test simplifier on negatives and integers. rational c (2, -5); // -2/5 rational d (-2, -5); // 2/5 rational e (3, -1); // -3 std::cout << c << " simplified is "; std::cout << c.simplify() << std::endl; std::cout << d << " simplified is "; std::cout << d.simplify() << std::endl; std::cout << e << " simplified is "; std::cout << e.simplify() << std::endl; }
Flowcharts are an excellent visual aid for illustrating complex structures and processes, as they provide a clear, step-by-step representation of how elements interact and progress. They simplify intricate information into easily digestible components, allowing viewers to grasp relationships and sequences at a glance. Additionally, diagrams or infographics can complement flowcharts by visualizing data or hierarchies, further enhancing understanding.
Inventions
The best tool for illustrating complex structures in processes is a flowchart. Flowcharts visually represent steps in a process using symbols and arrows, making it easier to understand the sequence and relationships between different components. Other useful tools include process mapping software and diagrams like swimlane charts, which can further clarify roles and responsibilities within the process. These tools help simplify complex information, making it more accessible and actionable.
Indeterminate structures offer several advantages, including enhanced load distribution, which helps to reduce stress concentrations and improve overall stability. They can also provide greater redundancy, allowing the structure to maintain safety and functionality even if one member fails. Additionally, indeterminate structures often enable more efficient use of materials, leading to potential cost savings and lighter designs. Lastly, they can simplify construction processes by minimizing the need for temporary supports during assembly.
Function key F4 repeats the last-done task on a new selection within a document.
-2/3 cannot be simplified. If the binary operator between -2 and 3 was meant to be something else, I apologise. Please resubmit the question with the operator written out in words.
No it will not simplify.
You can't simplify that. There are no common factors.You can't simplify that. There are no common factors.You can't simplify that. There are no common factors.You can't simplify that. There are no common factors.
You cannot simplify it.
Okay class, simplify the sum on the board.We need to simplify these instructions.
There is nothing to simplify. -2 is as simple as you can get.
The expression "5x - 13 47" seems to be missing an operator between -13 and 47. If you meant "5x - 13 + 47," you can simplify it to "5x + 34." If you meant something else, please clarify the expression.
simplify. Can you simplify this equation?
yes you can simplify 63
how do you simplify 108
You cannot simplify an integer.