You cannot design a full adder using only OR gates. You also need AND gates. Typically, this can be done with just NAND gates.
Do you mean :- how to get full adders by using half-adders? For this question refer following answer - A full-adder can be obtained by combining two half-adders and one or gate. Details on full-adder and half-adder can be referenced from following link http://www.fullchipdesign.com/fulladder.htm
give pin number 7, 11, 13, 14 to a 4input nand gate. this is the sum.give pin number 7, 9, 10, 12 to another 4input nand gate.this is the carry...
simply by complementing x input before applying to and gate for generating carry
by using 4 NCL gates we can design or implement a half adder.gates used in half adder are TH12[1 GATE],TH22[1 GATE] and TH24COMP0 [2 GATES].this NCL have a concept of DUAL-RAIL.output we get for this are S0,S1,Cout0,Cout1.
asdfghjkl;' s-sum and c'-carry see for half adder s=a(xor)b and c'=ab for full adder s=a(xor)b(xor)c and c=ab+bc+ac or ab+c(a(xor)b) we can convert two half adder to full adder with help of and or gate. . . ! we got two half adder * for first half adder input is a and b therefore. . .s=a(xor)b and c'=ab * for second half adder input is a(xor)b and c therefore. . .s=a(xor)b(xor)c and c' is (a(xor)b)c note: now connect the c' of first half adder and second half adder to 'or' gate resulting is ab+c(a(xor)b)
Logic circuit forplementation of a full adder using decoder and 2 or gate? Read more:Logic_circuit_forplementation_of_a_full_adder_using_decoder_and_2_or_gate
by the procedure design a half subtractor design a logic ciruit to add two numbers with five bits each drawthe logic diagram of afull adder using using NAND gates only ?
Do you mean :- how to get full adders by using half-adders? For this question refer following answer - A full-adder can be obtained by combining two half-adders and one or gate. Details on full-adder and half-adder can be referenced from following link http://www.fullchipdesign.com/fulladder.htm
Connect two half Adders with an OR gate to make a Full Adder.
give pin number 7, 11, 13, 14 to a 4input nand gate. this is the sum.give pin number 7, 9, 10, 12 to another 4input nand gate.this is the carry...
simply by complementing x input before applying to and gate for generating carry
by using 4 NCL gates we can design or implement a half adder.gates used in half adder are TH12[1 GATE],TH22[1 GATE] and TH24COMP0 [2 GATES].this NCL have a concept of DUAL-RAIL.output we get for this are S0,S1,Cout0,Cout1.
asdfghjkl;' s-sum and c'-carry see for half adder s=a(xor)b and c'=ab for full adder s=a(xor)b(xor)c and c=ab+bc+ac or ab+c(a(xor)b) we can convert two half adder to full adder with help of and or gate. . . ! we got two half adder * for first half adder input is a and b therefore. . .s=a(xor)b and c'=ab * for second half adder input is a(xor)b and c therefore. . .s=a(xor)b(xor)c and c' is (a(xor)b)c note: now connect the c' of first half adder and second half adder to 'or' gate resulting is ab+c(a(xor)b)
9,to implement a half adder 5 nand gates and for a full adder,another xor gate is required consisting of 4 nand gates. thus a total of 9 nand gates are required for a full adder.
A full adder can be constructed using basic logic gates: XOR, AND, and OR gates. Specifically, two XOR gates are used to calculate the sum, while two AND gates and one OR gate are employed to determine the carry-out. The first XOR gate takes the two input bits, and the second XOR gate incorporates the carry-in. The AND gates handle the carry generation, with the OR gate combining the outputs to produce the final carry-out.
Two half adders, an OR gate, and a delay.
an AND gate and an X-OR gate