It does work on d.c., but it really depends on what you want it to do!
All transformers are designed to work on AC. They do not work on DC.If you connect an inductor to DC, the current will increase until the capacity of the source or the conductance (1/resistance) capacity of the inductor and conductors is reached. Often, this condition will overheat and destroy the inductor, or destroy the source. A transformer is not an exception, as it is a form of inductor.
Yes, an inductor allows DC to pass through it. An inductor resists a change in current, proportional to inductance and voltage. At equilibirum, an ideal inductor has zero impedance. The differential equation for an inductor is di/dt = v / l
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
An inductor looks like a piece of wire to DC. It will thus look like a resistor, and inductor properties do not apply.
When a DC supply is applied to an inductor, it initially resists changes in current due to its property of self-inductance. As the current starts to flow, the inductor gradually stores energy in its magnetic field. Once the current reaches a steady state, the inductor behaves like a short circuit, allowing the current to flow freely without any opposition. Thus, in the long term, the inductor does not impede DC, allowing it to pass through.
All transformers are designed to work on AC. They do not work on DC.If you connect an inductor to DC, the current will increase until the capacity of the source or the conductance (1/resistance) capacity of the inductor and conductors is reached. Often, this condition will overheat and destroy the inductor, or destroy the source. A transformer is not an exception, as it is a form of inductor.
An inductor cannot work in dc because the frequency is zero there by making the inductive reactance zero as a consequenceAnswerOf course an inductor can work in a d.c. circuit!
Yes, an inductor allows DC to pass through it. An inductor resists a change in current, proportional to inductance and voltage. At equilibirum, an ideal inductor has zero impedance. The differential equation for an inductor is di/dt = v / l
In DC inductor is short circuited .
A DC shunt motor is a motor using DC supply with the the inductor connected parallel to the armature.
Depends on what you mean by work. It still opposes changes in the current flow through it, that doesn't change. But as DC has no phase, it produces no phase shifts as it does in AC.
Yes, an inductor is a short circuit to dc...that's true....IF the inductor is an ideal one, that is, the inductor has no resistance but has inductance only. Anything in real world, as you know, is not ideal. An inductor is usually made of a copper wire. A copper wire has its own resistance. If an inductor coil is thin and long (i.e. many turns), it will provide an appreciable resistance to DC, and will no longer be a short circuit.
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
Your question is confusing -is the inductor supplied with a.c. or d.c.?In either case, you can determine the inductance of an inductor by disconnecting it, and measuring its resistance with an ohmmeter. If you want a really accurate value of resistance, you could use a Wheatstone Bridge, instead.
An inductor looks like a piece of wire to DC. It will thus look like a resistor, and inductor properties do not apply.
i think in case of dc supply there will not be any induction
When a DC supply is applied to an inductor, it initially resists changes in current due to its property of self-inductance. As the current starts to flow, the inductor gradually stores energy in its magnetic field. Once the current reaches a steady state, the inductor behaves like a short circuit, allowing the current to flow freely without any opposition. Thus, in the long term, the inductor does not impede DC, allowing it to pass through.