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It's actually cos phi, where the Greek letter, 'phi', is the symbol for phase angle -the angle by which a load current lags or leads the supply current in an a.c. system (the Greek letter, 'theta', is used for the displacement of instantaneous values of current or voltage from the origin of a sine wave).
The reason why power factor is a cosine requires you to understand the relationship between apparent power, true power, and reactive power. Apparent power is the vector sum of true power and reactive power, and can be represented, graphically, by the so-called 'power triangle'. In the power triangle, true power lies along the horizontal axis, reactive power lies along the perpendicular axis, and the apparent power forms the hypotenuse, and the angle between true power and apparent power represents the phase angle. By definition, power factor is the ratio between true power and apparent power, and this ratio corresponds to the cosine of the phase angle.
From this, we can conclude that true power = apparent power x cos phi, where 'cos phi' is the 'factor' by which we must multiply apparent power to determine true power -i.e. the 'power factor'.
What else can I help you with?
How you measure power factor in three phase load by two wattmeter method?
First of all, you can only measure power factor of a three-phase load, provided that it is balanced load. The power factor can then be found by determining the cosine of the phase angle, using the following equation:tan (phase angle) = 1.732 ((P2-P1)/(P2+P1))...where P1 and P2 are the readings of the two wattmeters.
How to calculate a true power?
True power, measured in watts (W), can be calculated using the formula: ( P = VI \cos(\phi) ), where ( P ) is the true power, ( V ) is the voltage in volts, ( I ) is the current in amperes, and ( \phi ) is the phase angle between the voltage and current waveforms. This formula accounts for the power factor (cosine of the phase angle), which indicates the efficiency of power usage in an AC circuit. To find true power, you need to know the voltage, current, and phase angle or the power factor.
What is the difference between displacement and true power factor?
'Displacement power factor' is the technically-correct term used to describe the cosine of the phase angle (i.e. the angle by which the load current leads or lags the supply voltage) due to the reactance of a load. Usually, when we talk about the 'power factor' of a load, we mean 'displacement power factor'.However, another type of power factor can exist in a circuit, due to the presence of harmonics in the current waveform, due to non-linear loads such as SCR rectifiers. This type of power factor is temed 'distortion power factor', and may be corrected using filters.So, the terms 'displacement' and 'distortion' are used whenever it is necessary to clarify these different types of power factor.
How do you determine reactive power in three phase?
Total 3-phase real power = sqrt(3) x VLL x ILL x cos (theta) = 3 x Vp x Ip x cos (theta) Total 3-phase reactive power = sqrt(3) x VLL x ILL x sin (theta) = 3 x Vp x Ip x sin (theta) where: ?LL denotes line-to-line and ?p denotes phase-to-ground quantities Therefore, S = sqrt( P2+Q2) = = sqrt[32 x Vp2 x Ip2 x cos2 (theta) + 32 x Vp2 x Ip2 x sin2 (theta)] = sqrt[32 x Vp2 x Ip2 x {cos2 (theta) + sin2 (theta)}] = sqrt[32 x Vp2 x Ip2 x {1}] = 3 x Vp x Ip (works for the line-to-line case, as well) Hope this helps, Chris
How do you design power factor correction module for 3 phase?
using vienna rectifier
What is the angle of theta?
When used to indicate angles, "theta" is an unknown (exactly like using "x" for the unknown in equations).
What should be the angle between 2 vectors a?
The angle between two vectors a and b can be found using the dot product formula: a · b = |a| |b| cos(theta), where theta is the angle between the two vectors. Rearranging the formula, we can solve for theta: theta = arccos((a · b) / (|a| |b|)).
How do you calculate the angle for length 2700 and height 1680?
Using these two measurements you would calculate the angle using the tangent. In this case: tan (theta) = 1680/2700
How do you find the measure of a central angle from the radius?
To find the measure of a central angle in a circle using the radius, you can use the formula for arc length or the relationship between the radius and the angle in radians. The formula for arc length ( s ) is given by ( s = r \theta ), where ( r ) is the radius and ( \theta ) is the central angle in radians. Rearranging this formula, you can find the angle by using ( \theta = \frac{s}{r} ) if you know the arc length. In degrees, you can convert radians by multiplying by ( \frac{180}{\pi} ).
What is the angle of elevation of the sun when a flagpole M tall cast a shadow m long?
The angle of elevation of the sun can be determined using the tangent function in trigonometry. Specifically, if the height of the flagpole is ( M ) and the length of the shadow is ( m ), the angle of elevation ( \theta ) can be calculated using the formula ( \tan(\theta) = \frac{M}{m} ). To find the angle, use ( \theta = \arctan\left(\frac{M}{m}\right) ). This angle represents how high the sun is in the sky relative to the horizontal ground.
If the arc length of a sector in the unit circle is 4.2 what is the measure of the angle of the sector?
In a unit circle, the radius is 1, so the arc length ( s ) of a sector can be calculated using the formula ( s = r\theta ), where ( r ) is the radius and ( \theta ) is the angle in radians. Since the radius ( r = 1 ), the formula simplifies to ( s = \theta ). Therefore, if the arc length is 4.2, the measure of the angle of the sector is ( \theta = 4.2 ) radians.
What is an angle trisector?
An angle trisector is a line or ray that divides an angle into three equal smaller angles. In geometric terms, if an angle measures ( \theta ), each of the three angles created by the trisector will measure ( \theta/3 ). Angle trisectors can be constructed using specific geometric methods, but they cannot be constructed using just a compass and straightedge due to the limitations established by geometric construction theorems.
How angle between two vectors is found using cross product?
A x B = |A| |B| sin[theta]
How do you find the hypotenuse of a right triangle using sine?
The sine of an angle theta that is part of a right triangle, not the right angle, is the opposite side divided by the hypotenuse. As a result, you could determine the hypotenuse by dividing the opposite side by the sine (theta)...sine (theta) = opposite/hypotenusehypotenuse = opposite/sine (theta)...Except that this won't work when sine (theta) is zero, which it is when theta is a multiple of pi. In this case, of course, the right triangle degrades to a straight line, and the hypotenuse, so to speak, is the same as the adjacent side.
What angle do you use in he work equation?
In the work equation, the angle used is the angle between the direction of the force applied and the direction of the displacement. The work done (W) is calculated using the formula ( W = F \cdot d \cdot \cos(\theta) ), where ( F ) is the magnitude of the force, ( d ) is the displacement, and ( \theta ) is the angle. If the force and displacement are in the same direction, ( \theta ) is 0 degrees, and the cosine of 0 is 1, meaning all the force contributes to the work done.
What angle do you use in work equation?
In the work equation, the angle used is the angle between the direction of the force applied and the direction of displacement. The work done (W) is calculated using the formula ( W = F \cdot d \cdot \cos(\theta) ), where ( F ) is the magnitude of the force, ( d ) is the displacement, and ( \theta ) is the angle. If the force is in the same direction as the displacement, ( \theta ) is 0 degrees, and the work done is maximized. If the force is perpendicular to the displacement, the work done is zero.
How you measure power factor in three phase load by two wattmeter method?
First of all, you can only measure power factor of a three-phase load, provided that it is balanced load. The power factor can then be found by determining the cosine of the phase angle, using the following equation:tan (phase angle) = 1.732 ((P2-P1)/(P2+P1))...where P1 and P2 are the readings of the two wattmeters.
